Question

Which of the following hydrocarbons cannot be obtained by Sabatier and Senderens reaction?
A. \[{\rm{C}}{{\rm{H}}_{\rm{4}}}\]
B. \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{6}}}\]
C. \[{{\rm{C}}_{\rm{3}}}{{\rm{H}}_{\rm{8}}}\]
D. All

Answer 1

Hint: Sabatier and Senderens reaction is the reduction reaction of an unsaturated compound in presence of the nickel catalyst to obtain a saturated compound. Here, we have to identify the product which is not obtained by Sabatier and Senderens reaction.

Complete Step by Step Answer:
Let's first understand the reduction reaction in detail. In this reaction, the addition of hydrogen atoms to a compound takes place in presence of some catalysts such as nickel.
Let's discuss the options one by one.
Option B is \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{6}}}\]. This is a saturated compound obtained by method of Sabatier and Senderen's reaction of \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}\] . When ethene undergoes a reaction in the presence of catalyst, namely nickel, the formation of ethane occurs. The reaction is, \[{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}} \to {{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{6}}}\]. Therefore, this product can be obtained from this reaction.
Option C is \[{{\rm{C}}_{\rm{3}}}{{\rm{H}}_{\rm{8}}}\]. This is also a saturated compound and can be manufactured by the reduction reaction by Sanderson's method. So, this is also a product of Sanderson's method.

Option A is methane. This is also a saturated compound. But this compound cannot be manufactured by the method of Sendersen because this compound has only one atom of carbon. For the reduction reaction, the need of two carbon atoms is a must. Therefore, methane cannot be obtained by this method.
Therefore, option A is right.

Note: The use of Nickel catalyst in the hydrogenation reaction is common because of its cost-effective nature. It is cheaper than some other catalysts. Its appearance is a power of light gray colour. It is also used in the industrial manufacturing of hydrogen and carbon monoxide.