Courses
Courses for Kids
Free study material
Free LIVE classes
More

Two dice are thrown simultaneously. What is the probability that:
(i) 5 will not come upon either of them
(ii) 5 will come upon at least one
(iii) 5 will come up at both the dice

Last updated date: 26th Mar 2023
Total views: 312k
Views today: 2.89k
Answer
VerifiedVerified
312k+ views
Hint: Use probability=favorable cases/ total cases.

In a throw of pair of dice, total no of possible outcomes $ = 36\left( {6 \times 6} \right)$ which are:
$
  \left( {1,1} \right)\left( {1,2} \right)\left( {1,3} \right)\left( {1,4} \right)\left( {1,5} \right)\left( {1,6} \right) \\
  \left( {2,1} \right)\left( {2,2} \right)\left( {2,3} \right)\left( {2,4} \right)\left( {2,5} \right)\left( {2,6} \right) \\
  \left( {3,1} \right)\left( {3,2} \right)\left( {3,3} \right)\left( {3,4} \right)\left( {3,5} \right)\left( {3,6} \right) \\
  \left( {4,1} \right)\left( {4,2} \right)\left( {4,3} \right)\left( {4,4} \right)\left( {4,5} \right)\left( {4,6} \right) \\
  \left( {5,1} \right)\left( {5,2} \right)\left( {5,3} \right)\left( {5,4} \right)\left( {5,5} \right)\left( {5,6} \right) \\
  \left( {6,1} \right)\left( {6,2} \right)\left( {6,3} \right)\left( {6,4} \right)\left( {6,5} \right)\left( {6,6} \right) \\
$
(i) Let $E$ be the event of not getting a 5 on either of the two dice
Number of favorable outcomes=25
Total number of outcomes=36
$P\left( E \right) = \dfrac{{25}}{{36}}$
(ii) Let $E$ be the event of getting a 5 at least once
Number of favorable outcomes=11
Total number of outcomes=36
$P\left( E \right) = \dfrac{{11}}{{36}}$
(iii) Let $E$ be the event of getting a 5 on both dice
Number of favorable outcomes=1
Total number of outcomes=36
$P\left( E \right) = \dfrac{1}{{36}}$

Note: In the above solution the table made at the top containing the list of all possible outcomes is known as sample space of the event. In all the three parts of the solution, a number of favorable outcomes has been found out after counting the same from the above table.