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# How do you graph the function $f(x) = - 4x$ ?

Last updated date: 10th Aug 2024
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Hint:We need to draw the graph ‘x’ versus ‘y’. We give the random values for ‘x’ and we find the value of ‘f(x)’. We can give all real numbers for the value of ‘x’. Thus we will have coordinate points (x, y) (here ‘y’ is f(x)). Hence, we can plot the graph by using the values. We can also draw the graph using the intercept method.

Given $f(x) = - 4x$. Let's give the values for ‘x’ and we find the value of ‘f(x)’.
Put $x = 1$ in $f(x) = - 4x$ we have,
$f(1) = - 4 \times (1) = - 4$
Thus we have coordinate points $(1, - 4)$.
Put $x = - 1$in $f(x) = - 4x$ we have,
$f( - 1) = - 4 \times ( - 1) = 4$
Thus we have coordinate points $( - 1,4)$.
Put $x = 2$ in $f(x) = - 4x$ we have,
$f(2) = - 4 \times (2) = - 8$
Thus we have coordinate points $(2, - 8)$.
Put $x = - 2$in $f(x) = - 4x$ we have,
$f( - 2) = - 4 \times ( - 2) = 8$
Thus we have coordinate points $( - 2,8)$.
Put $x = 3$ in $f(x) = - 4x$ we have,
$f(3) = - 4 \times (3) = - 12$
Thus we have a coordinate point after rounding off is $(3, - 12)$.
Put $x = - 3$in $f(x) = - 4x$ we have,
$f( - 3) = - 4 \times ( - 3) = 12$
Thus we have coordinate point after rounding off is $( - 3,12)$.Thus we have,

 $x$ $1$ $- 1$ $2$ $- 2$ $3$ $- 3$ $y = f(x)$ $- 4$ $4$ $- 8$ $8$ $- 12$ $12$

Let’s draw the graph for these coordinates,

Note:A graph shows the relation between two variable quantities, it contains two axes perpendicular to each other namely the x-axis and the y-axis. Each variable is measured along one of the axes. In the question, we are given one linear equation containing two variables namely x and y, x is measured along the x-axis and y is measured along the y-axis while tracing the given equations.