Question

What transformation of energy takes place when current is drawn from a cell?
A.Chemical energy changes to electrical energy
B.Chemical energy changes to heat energy
C.Mechanical energy changes to electrical energy
D.Chemical energy changes to mechanical energy

Answer 1

Hint: To answer this question, recall the concept of energy extraction from a cell. A voltaic cell is also known as the galvanic cell is an electrochemical cell in which electrical energy is obtained from a spontaneous redox reaction that occurs inside the cell.

Complete step by step answer:
When the circuit is complete and current is being drawn from a cell, chemical energy is converted into electrical energy. A cell can be called a device, whose role is to convert chemical energy into electrical energy. Usually, in its basic structure, it includes two terminals, which are made up of metal: one terminal is positive, while the other one is negative.
Usually, a voltaic cell contains two different metals that are submerged in electrolytes and connected by a salt bridge. The half-cell is composed of solid metal which is immersed in the electrolytic solution. The full cell is composed of two half-cells. Generally, a salt bridge connects them both which prevents the ions of the more noble metal from plating out at the other electrode. In a voltaic cell, the anode is a negative electrode and oxidation takes place at the anode while cathode reduction takes place and it is the positive electrode. We should know that at the electrodes the reactions of electrons being absorbed or released are taking place. This process is known as discharging and this concept helps determine the release of ions on different electrodes.

Hence, the correct option is option A.

Note:
The increasing order of discharge of few cations is: \[{{\text{K}}^{\text{+}}}\text{, C}{{\text{a}}^{\text{2+}}}\text{, N}{{\text{a}}^{\text{+}}}\text{, M}{{\text{g}}^{\text{2+}}}\text{, A}{{\text{l}}^{\text{3+}}}\text{, Z}{{\text{n}}^{\text{2+}}}\text{, F}{{\text{e}}^{\text{2+}}}\text{, }{{\text{H}}^{\text{+}}}\text{, C}{{\text{u}}^{\text{2+}}}\text{, A}{{\text{g}}^{\text{+}}}\text{, A}{{\text{u}}^{\text{3+}}}\].
Increasing Order of discharge of few anions is: \[\text{S}{{\text{O}}_{\text{4}}}^{\text{2-}}\text{, N}{{\text{O}}_{\text{3}}}^{\text{-}}\text{, O}{{\text{H}}^{\text{-}}}\text{, C}{{\text{l}}^{\text{-}}}\text{, B}{{\text{r}}^{\text{-}}}\text{, }{{\text{I}}^{\text{-}}}\]