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How do we think the displacement of rod $AB$ will be affected if
(i) current in rod $AB$ is increased:
(ii) a stronger horse-shoe magnet is used:
(iii) length of the rod $AB$ is increased?

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Last updated date: 19th Jul 2024
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Answer
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Hint:A horseshoe magnet is a magnet shaped like a horseshoe or a U shape that has become the most commonly known magnet icon. William Sturgeon invented it in 1825. A permanent magnet or an electromagnet may be used for this kind of magnet.

Complete answer:
We now know that the force exerted by a magnet on a current bearing conductor is proportional to:
-The strength of the magnetic field: A magnet's magnetic force is directly proportional to the strength of the magnetic field.
-The amount of current flowing in the conductor: The magnetic force exerted by a magnet is equal to the current flowing through the conductor.
-The length of the conductor: A magnet's magnetic force is strictly proportional to the length of the conductor.

(i) If the current in rod $AB$ increases, so will the power. When the force increases, so will the displacement.
(ii) The power of the magnetic field increases as the magnet becomes heavier. When the magnetic field expands, so will the force. As a result, displacement will rise.
(iii) When the length of the conductor increases, so does the force. When the force increases, so will the displacement. As a result, displacement will rise in all three scenarios.

Note:A magnetic field is a vector field that represents the magnetic effect on moving charges, waves, and magnetic materials. A travelling charge in a magnetic field is subjected to a force that is perpendicular to both its own momentum and the magnetic field.