The slope of any line which is perpendicular to the x-axis is ____
A. 0
B. 1
C. -1
D. Not defined
Last updated date: 24th Mar 2023
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Answer
306k+ views
Hint: If we remember the plotting graph then we can remember that perpendicular to x-axis we have y-axis. Therefore, we need to find out the slope of the y-axis in order to solve this question. To calculate slope of a line we have the following formula- $m=\tan \theta $ where m=slope and $\theta $ is the smallest angle which the given line makes with the positive direction of x-axis.
“Complete step-by-step answer:”
The angle between the positive direction of x-axis and positive direction of y-axis is $\dfrac{\pi }{2}$ . Therefore, the slope of the positive y-axis is given by $m=\tan \dfrac{\pi }{2}$ which is not defined.
And the angle between the negative direction of y-axis and positive x-axis is $\dfrac{3\pi }{2}$ . Therefore, the slope of the negative y-axis is $m=\tan \dfrac{3\pi }{2}$ which is again undefined.
Hence, the correct option is option D.
Note: We also have the following result for perpendicular lines:
If ${{m}_{1}}$ is the slope of first line and ${{m}_{2}}$ is the slope of second line then if the lines are perpendicular ${{m}_{1}}\cdot {{m}_{2}}=-1$ .
But as we can see this result is not applicable to x-axis and y-axis because we have slope of x-axis=0 and y-axis=not defined. Therefore, we cannot multiply them and their multiplication is not equal to -1. But this is the only exception for this rule for lines in 2-D planes.
“Complete step-by-step answer:”
The angle between the positive direction of x-axis and positive direction of y-axis is $\dfrac{\pi }{2}$ . Therefore, the slope of the positive y-axis is given by $m=\tan \dfrac{\pi }{2}$ which is not defined.
And the angle between the negative direction of y-axis and positive x-axis is $\dfrac{3\pi }{2}$ . Therefore, the slope of the negative y-axis is $m=\tan \dfrac{3\pi }{2}$ which is again undefined.
Hence, the correct option is option D.
Note: We also have the following result for perpendicular lines:
If ${{m}_{1}}$ is the slope of first line and ${{m}_{2}}$ is the slope of second line then if the lines are perpendicular ${{m}_{1}}\cdot {{m}_{2}}=-1$ .
But as we can see this result is not applicable to x-axis and y-axis because we have slope of x-axis=0 and y-axis=not defined. Therefore, we cannot multiply them and their multiplication is not equal to -1. But this is the only exception for this rule for lines in 2-D planes.
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