
The sensitivity of a galvanometer is $60\,div/A$. When a shunt is used, its sensitivity becomes $10\,div/A$. If the galvanometer is of resistance \[20\Omega \], the value of shunt used is:
A. 4 \[\Omega \]
B. 5 \[\Omega \]
C. 20 \[\Omega \]
D. 2 \[\Omega \]
Answer
528.3k+ views
Hint:A galvanometer is an electric current measurement instrument that is electromechanical. Early galvanometers were uncalibrated, but later models, such as ammeters, were calibrated and could more accurately calculate current flow. Galvanometer is a device that uses the deflection of a moving coil to measure a small electrical current or a property of the current. The deflection is a mechanical rotation arising from the current's powers.
Complete step by step answer:
The current in microamperes needed to consume one millimetre deflection on a scale positioned 1 metre away from the mirror is known as the sensitivity of a galvanometer. If the current (I) q is small, the sensitivity would be high. As a result, the galvanometer's sensitivity can be improved by increasing the number of turns (N), using stronger magnets, or increasing the coil's region (A)
The sensitivity of a galvanometer is 60 div/A. When a shunt is used, its sensitivity becomes 10 div/A. Given the galvanometer is of resistance 20 \[\Omega \]. The galvanometer's sensitivity can be expressed as
\[\dfrac{{{{\mathbf{i}}_{\mathbf{g}}}}}{{\mathbf{i}}} = \dfrac{{\mathbf{S}}}{{{\mathbf{S}} + {\mathbf{G}}}}\]
$S$ = shunt and $G$ = Galvanometer.
According to the question,
\[\dfrac{{{{\mathbf{i}}_{\text{g}}}}}{{\text{i}}} = \dfrac{{10}}{{60}} \\
\Rightarrow \dfrac{{{{\mathbf{i}}_{\text{g}}}}}{{\text{i}}}= \dfrac{1}{6}\]
\[\Rightarrow G =20 \Omega \]
Upon substituting
\[ \Rightarrow \dfrac{1}{6} = \dfrac{{\mathbf{S}}}{{{\mathbf{S}} + {\mathbf{20}}}}\]
\[ \therefore {\mathbf{S}} = 4\Omega \]
Hence option A is correct.
Note:A shunt is a mechanism in electronics that provides a low-resistance path for electric current to travel through another point in the circuit. The word comes from the verb 'to shunt,' which means to turn around or take a different direction.
Complete step by step answer:
The current in microamperes needed to consume one millimetre deflection on a scale positioned 1 metre away from the mirror is known as the sensitivity of a galvanometer. If the current (I) q is small, the sensitivity would be high. As a result, the galvanometer's sensitivity can be improved by increasing the number of turns (N), using stronger magnets, or increasing the coil's region (A)
The sensitivity of a galvanometer is 60 div/A. When a shunt is used, its sensitivity becomes 10 div/A. Given the galvanometer is of resistance 20 \[\Omega \]. The galvanometer's sensitivity can be expressed as
\[\dfrac{{{{\mathbf{i}}_{\mathbf{g}}}}}{{\mathbf{i}}} = \dfrac{{\mathbf{S}}}{{{\mathbf{S}} + {\mathbf{G}}}}\]
$S$ = shunt and $G$ = Galvanometer.
According to the question,
\[\dfrac{{{{\mathbf{i}}_{\text{g}}}}}{{\text{i}}} = \dfrac{{10}}{{60}} \\
\Rightarrow \dfrac{{{{\mathbf{i}}_{\text{g}}}}}{{\text{i}}}= \dfrac{1}{6}\]
\[\Rightarrow G =20 \Omega \]
Upon substituting
\[ \Rightarrow \dfrac{1}{6} = \dfrac{{\mathbf{S}}}{{{\mathbf{S}} + {\mathbf{20}}}}\]
\[ \therefore {\mathbf{S}} = 4\Omega \]
Hence option A is correct.
Note:A shunt is a mechanism in electronics that provides a low-resistance path for electric current to travel through another point in the circuit. The word comes from the verb 'to shunt,' which means to turn around or take a different direction.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Giving reasons state the signs positive or negative class 12 physics CBSE

Explain esterification reaction with the help of a class 12 chemistry CBSE

What is defined as a solenoid Depict a diagram with class 12 physics CBSE

