
The probabilities of two events \[A\] and \[B\] are \[0.25\] and \[0.50\] respectively. The probability of both events occur simultaneously is \[0.14\]. Then what is the probability that neither \[A\] nor \[B\] occurs?
A. \[0.39\]
B. \[0.25\]
C. \[0.904\]
D. None of these
Answer
233.1k+ views
Hint: Use the formula of the probability of both events happening together and calculate the probability that the event is \[A\] or \[B\]. Then use the complement rule to reach the required answer.
Formula Used: Complement rule: The sum of the probabilities of an event and its complement is equal to 1.
\[P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right) - P\left( {A \cap B} \right)\]
Complete step by step solution:
Given:
\[P\left( A \right) = 0.25\], \[P\left( B \right) = 0.50\] and \[P\left( {A \cap B} \right) = 0.14\]
Let’s calculate the probability that the event is \[A\] or \[B\].
Apply the formula \[P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right) - P\left( {A \cap B} \right)\].
Substitute the given values.
\[P\left( {A \cup B} \right) = 0.25 + 0.50 - 0.14\]
\[ \Rightarrow \]\[P\left( {A \cup B} \right) = 0.75 - 0.14\]
\[ \Rightarrow \]\[P\left( {A \cup B} \right) = 0.61\]
Now calculate the probability that neither \[A\] nor \[B\] occurs.
The complement of \[P\left( {A \cup B} \right)\] is the probability that neither \[A\] nor \[B\] occurs.
Apply the complement rule.
\[P\left( {A \cup B} \right) + P{\left( {A \cup B} \right)^\prime } = 1\]
Simplify the above equation.
\[P\left( {A \cup B} \right) + P\left( {{A^\prime } \cap {B^\prime }} \right) = 1\] [Since \[P{\left( {A \cup B} \right)^\prime } = P\left( {{A^\prime } \cap {B^\prime }} \right)\]]
\[ \Rightarrow \]\[P\left( {{A^\prime } \cap {B^\prime }} \right) = 1 - P\left( {A \cup B} \right)\]
Substitute \[P\left( {A \cup B} \right) = 0.61\] in the above equation.
\[P\left( {{A^\prime } \cap {B^\prime }} \right) = 1 - 0.61\]
\[ \Rightarrow \]\[P\left( {{A^\prime } \cap {B^\prime }} \right) = 0.39\]
Hence the correct option is A.
Note: Probability means how likely something is to happen. The range of the probability of an event is \[\left[ {0,1} \right]\].
The complement of an event \[A\] is the set of all outcomes in the sample space that are not included in the outcomes of event \[A\]. It is represented by \[A'\], \[{A^C}\] or \[\overline A \].
Formula Used: Complement rule: The sum of the probabilities of an event and its complement is equal to 1.
\[P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right) - P\left( {A \cap B} \right)\]
Complete step by step solution:
Given:
\[P\left( A \right) = 0.25\], \[P\left( B \right) = 0.50\] and \[P\left( {A \cap B} \right) = 0.14\]
Let’s calculate the probability that the event is \[A\] or \[B\].
Apply the formula \[P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right) - P\left( {A \cap B} \right)\].
Substitute the given values.
\[P\left( {A \cup B} \right) = 0.25 + 0.50 - 0.14\]
\[ \Rightarrow \]\[P\left( {A \cup B} \right) = 0.75 - 0.14\]
\[ \Rightarrow \]\[P\left( {A \cup B} \right) = 0.61\]
Now calculate the probability that neither \[A\] nor \[B\] occurs.
The complement of \[P\left( {A \cup B} \right)\] is the probability that neither \[A\] nor \[B\] occurs.
Apply the complement rule.
\[P\left( {A \cup B} \right) + P{\left( {A \cup B} \right)^\prime } = 1\]
Simplify the above equation.
\[P\left( {A \cup B} \right) + P\left( {{A^\prime } \cap {B^\prime }} \right) = 1\] [Since \[P{\left( {A \cup B} \right)^\prime } = P\left( {{A^\prime } \cap {B^\prime }} \right)\]]
\[ \Rightarrow \]\[P\left( {{A^\prime } \cap {B^\prime }} \right) = 1 - P\left( {A \cup B} \right)\]
Substitute \[P\left( {A \cup B} \right) = 0.61\] in the above equation.
\[P\left( {{A^\prime } \cap {B^\prime }} \right) = 1 - 0.61\]
\[ \Rightarrow \]\[P\left( {{A^\prime } \cap {B^\prime }} \right) = 0.39\]
Hence the correct option is A.
Note: Probability means how likely something is to happen. The range of the probability of an event is \[\left[ {0,1} \right]\].
The complement of an event \[A\] is the set of all outcomes in the sample space that are not included in the outcomes of event \[A\]. It is represented by \[A'\], \[{A^C}\] or \[\overline A \].
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding Electromagnetic Waves and Their Importance

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding How a Current Loop Acts as a Magnetic Dipole

