The pair of equations $x=a$ and $y=b$ graphically represents lines which are:
A.Parallel
B.Intersecting at $\left( b,a \right)$
C.Coincident
D.Intersecting at $\left( a,b \right)$
Answer
570.4k+ views
Hint: The \[x\] coordinate of a point determines its distance from the \[y\] axis and the \[y\] coordinate of the point determines its distance from the \[x\] axis . A line parallel to the $x$ axis is of the form $y=c$ and a line parallel to the $y$ axis is of the form $x=c$ , where $c$ is any constant.
Complete step-by-step answer:
Before plotting the points , we must know about the coordinate system.
The cartesian coordinate system is a system of identifying the location of a point with respect to two perpendicular lines , known as coordinate axes. The vertical axis is called the \[y\] axis and the horizontal axis is called the \[x\] axis. The point of intersection of these axes is called the origin and it is represented by the ordered pair \[(0,0)\]. The distance of a point from the \[y\] axis is called the \[x\]coordinate and the distance of the point from \[x\] axis is called the \[y\] coordinate of the point. The equation of a line passing through a point $\left( {{x}_{1}},{{y}_{1}} \right)$ is given as $y-{{y}_{1}}=m\left( x-{{x}_{1}} \right)$ , where $m$ is the slope of the line. Now, if the line is parallel to the $x$ axis, then its slope is equal to zero . So, the equation of the line will be $y-{{y}_{1}}=0$ . So, the $y$ coordinate of any point on the line will be ${{y}_{1}}$. Similarly, if the line is parallel to the $y$ axis, then the slope of the line will be equal to infinity, and the equation of the line will be of the form $x-{{x}_{1}}=0$ . So, the $x$ coordinate of any point on the line will be ${{x}_{1}}$.
Now, coming to the question, the pair of equations given to us are $x=a$ and $y=b$. The equation $x=a$ is of the form $x-{{x}_{1}}=0$ , and hence, represents a line parallel to $y$ axis at a distance of $a$ units from it. Similarly, the equation $y=b$ is of the form $y-{{y}_{1}}=0$ , and hence, represents a line parallel to the $x$ axis at a distance of $b$ units from it. Hence, the two lines are perpendicular and therefore, will intersect at a point. Now, any point on the line $x=a$ will have its $x$ coordinate equal to $a$ and any point on the line $y=b$ will have its $y$ coordinate equal to $b$ . So, the coordinates of the point of intersection of the lines $x=a$ and $y=b$ will be $\left( a,b \right)$ .
This can be represented graphically as:
So, the lines $x=a$ and $y=b$ are intersecting lines and they intersect at the point $\left( a,b \right)$.
Hence, option D. is the correct option.
Note: Students get confused and write that the line $x=a$ is parallel to the $x$ axis , which is wrong. Such confusion should be avoided.
Complete step-by-step answer:
Before plotting the points , we must know about the coordinate system.
The cartesian coordinate system is a system of identifying the location of a point with respect to two perpendicular lines , known as coordinate axes. The vertical axis is called the \[y\] axis and the horizontal axis is called the \[x\] axis. The point of intersection of these axes is called the origin and it is represented by the ordered pair \[(0,0)\]. The distance of a point from the \[y\] axis is called the \[x\]coordinate and the distance of the point from \[x\] axis is called the \[y\] coordinate of the point. The equation of a line passing through a point $\left( {{x}_{1}},{{y}_{1}} \right)$ is given as $y-{{y}_{1}}=m\left( x-{{x}_{1}} \right)$ , where $m$ is the slope of the line. Now, if the line is parallel to the $x$ axis, then its slope is equal to zero . So, the equation of the line will be $y-{{y}_{1}}=0$ . So, the $y$ coordinate of any point on the line will be ${{y}_{1}}$. Similarly, if the line is parallel to the $y$ axis, then the slope of the line will be equal to infinity, and the equation of the line will be of the form $x-{{x}_{1}}=0$ . So, the $x$ coordinate of any point on the line will be ${{x}_{1}}$.
Now, coming to the question, the pair of equations given to us are $x=a$ and $y=b$. The equation $x=a$ is of the form $x-{{x}_{1}}=0$ , and hence, represents a line parallel to $y$ axis at a distance of $a$ units from it. Similarly, the equation $y=b$ is of the form $y-{{y}_{1}}=0$ , and hence, represents a line parallel to the $x$ axis at a distance of $b$ units from it. Hence, the two lines are perpendicular and therefore, will intersect at a point. Now, any point on the line $x=a$ will have its $x$ coordinate equal to $a$ and any point on the line $y=b$ will have its $y$ coordinate equal to $b$ . So, the coordinates of the point of intersection of the lines $x=a$ and $y=b$ will be $\left( a,b \right)$ .
This can be represented graphically as:
So, the lines $x=a$ and $y=b$ are intersecting lines and they intersect at the point $\left( a,b \right)$.
Hence, option D. is the correct option.
Note: Students get confused and write that the line $x=a$ is parallel to the $x$ axis , which is wrong. Such confusion should be avoided.
Recently Updated Pages
Master Class 7 Science: Engaging Questions & Answers for Success

Master Class 7 English: Engaging Questions & Answers for Success

Master Class 7 Maths: Engaging Questions & Answers for Success

Class 7 Question and Answer - Your Ultimate Solutions Guide

Master Class 6 English: Engaging Questions & Answers for Success

Master Class 6 Maths: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

The total number of vertebrae in man is a30 b31 c32 class 12 biology CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

The number of cranial nerves in a frog is A 10 pairs class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Differentiate between Pyramid of energy and pyramid class 12 biology CBSE

