Answer
396.9k+ views
Hint:$10\% $ by w/w solution of glucose means there is $10g$ of glucose and $90g$ of water in $100g$ of solution. And the Molality is calculated by no. of moles of solute/ mass of solvent in Kilograms. The concentrations which are expressed in molality are used while studying properties of solutions
Formula Used:Molality no. of moles of solute/ mass of solvent
Complete step by step answer:
Here, mass of glucose is $10g$ as given in the question:
Moles of glucose = $10/180 = 0.556mole$
Molality is the total number of moles of a solute present in $1$ kilogram of a solvent.
We can say that, molality= number of moles of solute/ mass of solvent in Kg. Molality is expressed by “m”.
Formula of glucose is ${C_6}{H_{12}}{O_6}$ hence,
Atomic mass of carbon= $12g$
Atomic mass of hydrogen = $1g$
Atomic mass of oxygen= $16g$
Molecular weight of glucose=$(12*6) + (1*12) + (16*6) = 180$
The solution of glucose in water which is $10\% $ w/w implies $10g$ of glucose in $100g$ of solution
Mass of solute= $10g$
Mass of solution=$100g$
Mass of solvent=$(100 - 10)g = 90g = 0.090Kg$
Molality = $0.556/0.090 = 0.617m$
Hence, option (B) is the correct option.
Additional Information:
Some uses of molality is: The concentrations which are expressed in molality are used while studying properties of solutions linked to vapor pressure and temperature changes. Molality is also used because its value does not change with variations in temperature. The volume of a solution, on the other hand, is somewhat dependent upon temperature.
Note:
Molarity is expressed by “M” whereas molality is expressed by “m” and these both express the concentration of a chemical solution. And always remember that $10\% $By w/w solution of glucose means there is $10g$ of glucose and $90g$ of water in $100g$ of solution. It will help in solving the problem given.
Formula Used:Molality no. of moles of solute/ mass of solvent
Complete step by step answer:
Here, mass of glucose is $10g$ as given in the question:
Moles of glucose = $10/180 = 0.556mole$
Molality is the total number of moles of a solute present in $1$ kilogram of a solvent.
We can say that, molality= number of moles of solute/ mass of solvent in Kg. Molality is expressed by “m”.
Formula of glucose is ${C_6}{H_{12}}{O_6}$ hence,
Atomic mass of carbon= $12g$
Atomic mass of hydrogen = $1g$
Atomic mass of oxygen= $16g$
Molecular weight of glucose=$(12*6) + (1*12) + (16*6) = 180$
The solution of glucose in water which is $10\% $ w/w implies $10g$ of glucose in $100g$ of solution
Mass of solute= $10g$
Mass of solution=$100g$
Mass of solvent=$(100 - 10)g = 90g = 0.090Kg$
Molality = $0.556/0.090 = 0.617m$
Hence, option (B) is the correct option.
Additional Information:
Some uses of molality is: The concentrations which are expressed in molality are used while studying properties of solutions linked to vapor pressure and temperature changes. Molality is also used because its value does not change with variations in temperature. The volume of a solution, on the other hand, is somewhat dependent upon temperature.
Note:
Molarity is expressed by “M” whereas molality is expressed by “m” and these both express the concentration of a chemical solution. And always remember that $10\% $By w/w solution of glucose means there is $10g$ of glucose and $90g$ of water in $100g$ of solution. It will help in solving the problem given.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)