Answer
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Hint: The naming of the given compound is done by a set of rules for coordination complexes, in which the one part is cation and the other is anion and the cation is always named before anion. t Dimethyl glyoxime is a chelate i.e. it donates the electrons to the central metal atom through the two donor atoms and when this is made to undergo reaction with the aqueous solution of nickel.
Complete answer:
First of all, let’s discuss what dimethylglyoxime is. Dimethylglyoxime is the chelating ligands and are those ligands (those molecules which are attached to the central metal atom through the coordinate bonds) which binds the central metal atom through two or more donor atoms of the ligands and results in the formation of cyclic ring compounds known as chelates and the process is known as chelation.
Ligands that go about as anions which end in "- ide" are supplanted with a consummation "" (e.g., Chloride \[\to \] Chloro). Anions finishing with "- ite" and "- ate" are supplanted with endings "- ito" and "- ato" individually (e.g., Nitrite \[\to \] Nitrito, Nitrate\[\to \] Nitrato).
Most nonpartisan particles that are ligands convey their typical name. The couple of special cases are the initial four on the outline: ammine, water, carbonyl, and nitrosyl. The quantity of ligands present in the complex is shown with the prefixes di, tri, and so forth the special cases are polydentates that have a prefix effectively in their name (en and EDTA-are the most widely recognized).
When naming the metal community, you should know the conventional metal name and the oxidation state. To show the oxidation state, we utilize Roman numerals inside brackets. The IUPAC name of the red coloured compound complex $[Fe{{({{C}_{4}}{{H}_{7}}{{O}_{2}}{{N}_{2}})}_{2}}]$ obtained from the reaction of $F{{e}^{2+}}$ and dimethylglyoxime is bis(dimethylglyoximato)iron$(II)$ ; $F{{e}^{2+}}+2{{C}_{4}}{{H}_{7}}{{O}_{2}}{{N}_{2}}^{-}\to [Fe{{({{C}_{4}}{{H}_{7}}{{O}_{2}}{{N}_{2}})}_{2}}]$.
Therefore, option (B) is the correct answer.
Note:
Remember to calculate carefully the charge on metal ions and ligands because they help in finding the naming of the compound and oxidation number of the given compound. Chelates or the chelated complexes have been found to be much more stable than the similar complexes with unidentate ligand (uni means one and dentate refers to the denticity which means the number the donor groups which can donate electron to the central metal atom and forms the coordinate bond with it).
Complete answer:
First of all, let’s discuss what dimethylglyoxime is. Dimethylglyoxime is the chelating ligands and are those ligands (those molecules which are attached to the central metal atom through the coordinate bonds) which binds the central metal atom through two or more donor atoms of the ligands and results in the formation of cyclic ring compounds known as chelates and the process is known as chelation.
Ligands that go about as anions which end in "- ide" are supplanted with a consummation "" (e.g., Chloride \[\to \] Chloro). Anions finishing with "- ite" and "- ate" are supplanted with endings "- ito" and "- ato" individually (e.g., Nitrite \[\to \] Nitrito, Nitrate\[\to \] Nitrato).
Most nonpartisan particles that are ligands convey their typical name. The couple of special cases are the initial four on the outline: ammine, water, carbonyl, and nitrosyl. The quantity of ligands present in the complex is shown with the prefixes di, tri, and so forth the special cases are polydentates that have a prefix effectively in their name (en and EDTA-are the most widely recognized).
When naming the metal community, you should know the conventional metal name and the oxidation state. To show the oxidation state, we utilize Roman numerals inside brackets. The IUPAC name of the red coloured compound complex $[Fe{{({{C}_{4}}{{H}_{7}}{{O}_{2}}{{N}_{2}})}_{2}}]$ obtained from the reaction of $F{{e}^{2+}}$ and dimethylglyoxime is bis(dimethylglyoximato)iron$(II)$ ; $F{{e}^{2+}}+2{{C}_{4}}{{H}_{7}}{{O}_{2}}{{N}_{2}}^{-}\to [Fe{{({{C}_{4}}{{H}_{7}}{{O}_{2}}{{N}_{2}})}_{2}}]$.
Therefore, option (B) is the correct answer.
Note:
Remember to calculate carefully the charge on metal ions and ligands because they help in finding the naming of the compound and oxidation number of the given compound. Chelates or the chelated complexes have been found to be much more stable than the similar complexes with unidentate ligand (uni means one and dentate refers to the denticity which means the number the donor groups which can donate electron to the central metal atom and forms the coordinate bond with it).
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