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**Hint:**A function with a graph that moves downward as it is followed from left to right is known as decreasing function. Differentiate the function and then equate with 0 to find the values.

**Complete step-by-step answer:**$f(x)=1-x^3-x^5$

Now we differentiate the function,

$f’(x)=\dfrac{d}{dx} f’(x) =0-3x^2-5x^4$

Now we find the values after differentiating,

$\Rightarrow f’(x) =-3x^2-5x^4$

Now we take constants from the LHS common,

$\Rightarrow f’(x) =-x^2(3+5x^2)$

f’(x) = 0 when x = 0

x = 0 is the only critical point because $3+5x^2 >0 \forall x \in R $

f is decreasing on all the x value $ x \in R $

because f’(x)<0 for all $ x \in R $

**Therefore , the correct option is d) all the values of x**

**Note:**We need to differentiate the function and not integrate it. Students often go wrong in this step. Now students need to equate the differentiated equation with 0 to find the values of x. This step is very important as otherwise students would not be able to find the values for x.

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