Answer
425.4k+ views
Hint:
When solute particles are added to any pure liquid or solution, they tend to separate the solvent molecules because of the interference of the solute particles. This interference causes a lowering in the freezing point of the pure solvent. This concept is known as freezing point depression.
Formula Used: \[\Delta {T_f} = {K_f} \times molality\]
Complete step by step answer:
The freezing point of any liquid is basically the temperature at which the free flowing mobility of the molecules of the liquid state is restricted, and due to such immobility of molecules, the given substance transforms from solid state to liquid state.
This depression in the freezing point can be mathematically formulated and calculated. The depression in the freezing point or the difference in temperature is directly proportional to the molality of the solute. This relation is equated by introducing a constant known as the molal freezing point depression constant. Mathematically, this can be represented as:
\[\therefore {K_f} = \dfrac{{0.25}}{{\Delta {T_f}}}\]
Where, \[\Delta {T_f}\]is the depression in the freezing point,
\[{K_f}\] is molal freezing point depression constant,
m is the molality of the solute.
Rearranging this equation, we get,
\[{K_f} = \dfrac{{\Delta {T_f}}}{m}\]
\[{K_f} = \dfrac{{\Delta {T_f}}}{{0.25}}\]
Here, \[\Delta {T_f}\]= 278.8K – 276.8K = 2K
Hence,
\[\therefore {K_f} = \dfrac{2}{{0.25}}\]
\[\therefore {K_f} = 8K.kg.mo{l^{ - 1}}\]
Hence, the molal depression constant of nitrobenzene is\[8K.kg.mo{l^{ - 1}}\].
Note:
In case the molality of the solute is not given, then the molality can be calculated as a ratio of the number of moles of the solute to the weight of the solvent in kg.
When solute particles are added to any pure liquid or solution, they tend to separate the solvent molecules because of the interference of the solute particles. This interference causes a lowering in the freezing point of the pure solvent. This concept is known as freezing point depression.
Formula Used: \[\Delta {T_f} = {K_f} \times molality\]
Complete step by step answer:
The freezing point of any liquid is basically the temperature at which the free flowing mobility of the molecules of the liquid state is restricted, and due to such immobility of molecules, the given substance transforms from solid state to liquid state.
This depression in the freezing point can be mathematically formulated and calculated. The depression in the freezing point or the difference in temperature is directly proportional to the molality of the solute. This relation is equated by introducing a constant known as the molal freezing point depression constant. Mathematically, this can be represented as:
\[\therefore {K_f} = \dfrac{{0.25}}{{\Delta {T_f}}}\]
Where, \[\Delta {T_f}\]is the depression in the freezing point,
\[{K_f}\] is molal freezing point depression constant,
m is the molality of the solute.
Rearranging this equation, we get,
\[{K_f} = \dfrac{{\Delta {T_f}}}{m}\]
\[{K_f} = \dfrac{{\Delta {T_f}}}{{0.25}}\]
Here, \[\Delta {T_f}\]= 278.8K – 276.8K = 2K
Hence,
\[\therefore {K_f} = \dfrac{2}{{0.25}}\]
\[\therefore {K_f} = 8K.kg.mo{l^{ - 1}}\]
Hence, the molal depression constant of nitrobenzene is\[8K.kg.mo{l^{ - 1}}\].
Note:
In case the molality of the solute is not given, then the molality can be calculated as a ratio of the number of moles of the solute to the weight of the solvent in kg.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)