
The force between two magnetic poles is F when they are separated by a certain distance. If the distance between the two poles is doubled and the strength of each pole is tripled. The percentage change in the force between the two poles is:
A) 125%
B) 100%
C) 50%
D) 25%
Answer
558.9k+ views
Hint The force between two magnetic poles is proportional to the product of the strength of the magnetic poles and inversely proportional to the square of the distance between these two magnetic poles. We will use this relation to determine the percentage increase in the poles when the pole strength is tripled and the distance between the poles is doubled.
Formula used: In this question, we will use the following formula
$\Rightarrow F = \dfrac{{{\mu _0}{M_1}{M_2}}}{{4\pi {d^2}}}$ where $F$ is the force between two magnetic poles of strength ${M_1}$ and ${M_2}$ at a distance $d$
Complete step by step answer
We know that the force between two magnetic poles of strength ${M_1}$ and ${M_2}$ at a distance $d$ can be calculated as:
$\Rightarrow F = \dfrac{{{\mu _0}{M_1}{M_2}}}{{4\pi {d^2}}}$
Now, we’ve been told that the distance between the two poles is doubled i.e. $d' = 3d$ and the strength of each pole is tripled, which implies${M_1}' = 3{M_1}$ and ${M_2}' = 3{M_2}$
So, the new force between these two poles will be
$\Rightarrow F' = \dfrac{{{\mu _0}{M_1}'{M_2}'}}{{d{'^2}}}$
On substituting $d' = 3d$, ${M_1}' = 3{M_1}$ and ${M_2}' = 3{M_2}$, we get,
$\Rightarrow F' = \dfrac{9}{4}\dfrac{{{\mu _0}{M_1}{M_2}}}{{4\pi {d^2}}}$
$\Rightarrow F' = \dfrac{9}{4}F$
The percentage increase in the force can be calculated as,
$\Rightarrow \% = \dfrac{{{\text{New force - old force}}}}{{{\text{Old force}}}} \times 100$
$\Rightarrow \% = \dfrac{{\dfrac{9}{4}F - F}}{F} \times 100$
On dividing the numerator and denominator by $F$, we get
$\% = 125\% $ which corresponds to option (A).
Note
Here we have assumed that the poles are in a vacuum which means there is no medium between them and there are no other magnetic poles in their vicinity that will affect the force they experience. We must be careful since we’ve been asked to find the percentage of the change in the force as compared to the old scenario and not the ratio of the two forces. Since the force is increased by 125%, it is more than doubled in the new scenario.
Formula used: In this question, we will use the following formula
$\Rightarrow F = \dfrac{{{\mu _0}{M_1}{M_2}}}{{4\pi {d^2}}}$ where $F$ is the force between two magnetic poles of strength ${M_1}$ and ${M_2}$ at a distance $d$
Complete step by step answer
We know that the force between two magnetic poles of strength ${M_1}$ and ${M_2}$ at a distance $d$ can be calculated as:
$\Rightarrow F = \dfrac{{{\mu _0}{M_1}{M_2}}}{{4\pi {d^2}}}$
Now, we’ve been told that the distance between the two poles is doubled i.e. $d' = 3d$ and the strength of each pole is tripled, which implies${M_1}' = 3{M_1}$ and ${M_2}' = 3{M_2}$
So, the new force between these two poles will be
$\Rightarrow F' = \dfrac{{{\mu _0}{M_1}'{M_2}'}}{{d{'^2}}}$
On substituting $d' = 3d$, ${M_1}' = 3{M_1}$ and ${M_2}' = 3{M_2}$, we get,
$\Rightarrow F' = \dfrac{9}{4}\dfrac{{{\mu _0}{M_1}{M_2}}}{{4\pi {d^2}}}$
$\Rightarrow F' = \dfrac{9}{4}F$
The percentage increase in the force can be calculated as,
$\Rightarrow \% = \dfrac{{{\text{New force - old force}}}}{{{\text{Old force}}}} \times 100$
$\Rightarrow \% = \dfrac{{\dfrac{9}{4}F - F}}{F} \times 100$
On dividing the numerator and denominator by $F$, we get
$\% = 125\% $ which corresponds to option (A).
Note
Here we have assumed that the poles are in a vacuum which means there is no medium between them and there are no other magnetic poles in their vicinity that will affect the force they experience. We must be careful since we’ve been asked to find the percentage of the change in the force as compared to the old scenario and not the ratio of the two forces. Since the force is increased by 125%, it is more than doubled in the new scenario.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

