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# The element of ${{s}^{2}}{{p}^{2}}$ configuration is of group:A) IVB) IIIC) VD) II

Last updated date: 20th Jun 2024
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Hint: The groups of the elements to which they belong is calculated using the number of valence electrons. Each group is represented using each general electronic configuration.

Here it is asked that, to which group the element with${{s}^{2}}{{p}^{2}}$ configuration belongs to, so the given is the general configuration of the group .As s orbital have 2 electrons and another 2 electrons are present in the p orbital so they both give a value of 4 electrons in the valence shell.
${{s}^{2}}{{p}^{2}}$ Configuration = 2 s electrons + 2 p electrons = 4 electrons
So there are 4 electrons in the valence shells, which is the general configuration of ${{14}^{th}}$ group element or IV- A group element.
Note: We know there are 4 electrons in the outer shell and the valency of the element is 4.But we may sometimes write that the element may belong to the 4TH group elements placed in the periodic table but here ${{4}^{th}}$ group represents the elements with valency 4. ${{15}^{th}}$ Group elements are called as V-A groups elements etc.