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# The density of $KBr$ is $2.7$$gc{m^{ - 3}}. The length of the unit cell is 654pm. Atomic mass of amu K = 39, Br = 80. Then the solid is?A.Face centered simpleB.Simple cubic systemC.Body centered cubic systemD.None of the above Last updated date: 14th Jul 2024 Total views: 345.3k Views today: 5.45k Answer Verified 345.3k+ views Hint :Solids are classified according to the orientation of their atoms. A unit cell is the smallest unit of the crystal lattice. Repeating unit cells forms a whole crystal solid. Complete Step By Step Answer: In a simple cubic system, only a single atom is located at the corner of the lattice. The number of unit cells present is 4. Every atom is shared by 8unit cells. The body center cube is similar to a simple cubic structure except it has a single atom in the center of the entire lattice. It has one atom at each corner. In the face centered cubic unit cell atoms are present on all corners and one atom is present on each plane as well. There is no center atom present at the center of the lattice. Now density of the unit cell is defined by d = \dfrac{{z \times m}}{{{a^3} \times {N_o}}} z = \dfrac{{d \times {a^3} \times {N_o}}}{m} Here d = density z = Number of atoms per unit cell m = Molecular weight a = Edge length {N_o} = Avogadro’s number, which is 6.023 \times {10^{23}} The total molecular weight is 39 + 80 = 119 So therefore we solve as z =$$\dfrac{{2.75 \times {{\left( {654 \times {{10}^{ - 10}}} \right)}^3} \times 6.023 \times {{10}^{23}}}}{{119}}$
$z = 4$
Therefore $4$ molecules of $KBr$ are present in the unit cell.
Hence it is a face-centered cubic unit cell.

Hence, option (C) body centered cubic center is correct.

Note :
In a simple cubic system, a unit cell has ${18^{th}}$of an atom. There are seven different types of a unit cell like cubic, tetragonal, orthorhombic, triclinic, monoclinic, hexagonal and rhombohedral. The difference between them is their angle and crystallographic axes.