
The degree of dissociation of a weak electrolyte is proportional to its molar conductance. Explain.
Answer
574.8k+ views
Hint: The degree of dissociation is the fraction of original solute molecules that have dissociated. It is usually dissociated by Greek symbol $ \propto $. More accurately, degree of dissociation refers to the amount of solute dissociated into ions or radicals per mole.
Complete step by step answer:
The second class of category of compounds, referred to as weak electrolytes, are those where ionization is incomplete. The ionization will increase with dilution and hence the molar conductivity increases with dilution. Thus, we can say that the conductivity is directly proportional to the degree of dissociation of electrolyte..
For weak electrolytes, the graph plotted between molar conductivity $\sqrt C $ (where $C$ is the concentration) is not a straight line. This is because weak electrolytes have lower molar conductivities and lower degree of dissociation at higher concentration which increases steeply at lower concentration. Hence, we use Kohlrausch law of independent migration of ions for determining to limit molar conductivity $E_n^\circ$ for weak electrolyte.
Additional Information:
Let us consider weak electrolyte $AB$.
$AB \rightleftharpoons {A^ + } + {B^ - }$
\[l = 0,{\text{ C 0 0}}\] $ \propto \to {\text{degree }}of{\text{ }}dissociation$
\[t = t,{\text{ }}C - C \propto {\text{ }}C \propto {\text{ }}C \propto \]\[\]
$K = \dfrac{{\left[ {{A^ + }} \right]\left[ {{B^ - }} \right]}}{{\left[ {AB} \right]}} = \dfrac{{\left( {C \propto } \right)\left( {C \propto } \right)}}{{C\left( {1 - \propto } \right)}} = \dfrac{{{ \propto ^2}C}}{{1 - \propto }}$
For weak electrolyte, $ \propto \ll 1$
This implies that $\left( {1 - \propto } \right) \approx 1$
$K = \dfrac{{{ \propto ^2}C}}{{1 - \propto }} = { \propto ^2}C$
So, from this we can say that
$ \propto = \sqrt {\dfrac{K}{C}} $
Thus, it is clear that the degree of dissociation of weak electrolyte is proportional to the inverse square root of the concentration, or the square root of dilution. The concentration of any one ionic species is given by the root of the product of the dissociation constant and concentration of electrolyte.
$\left[ {{A^ + }} \right] = \left[ {{B^ - }} \right] = \propto C = \sqrt {KC} $
Note:
Weak electrolyte, like weak acids and bases partially ionize in solution. On the other hand, strong electrolytes completely or almost completely ionize or dissociate and have many ions.
Complete step by step answer:
The second class of category of compounds, referred to as weak electrolytes, are those where ionization is incomplete. The ionization will increase with dilution and hence the molar conductivity increases with dilution. Thus, we can say that the conductivity is directly proportional to the degree of dissociation of electrolyte..
For weak electrolytes, the graph plotted between molar conductivity $\sqrt C $ (where $C$ is the concentration) is not a straight line. This is because weak electrolytes have lower molar conductivities and lower degree of dissociation at higher concentration which increases steeply at lower concentration. Hence, we use Kohlrausch law of independent migration of ions for determining to limit molar conductivity $E_n^\circ$ for weak electrolyte.
Additional Information:
Let us consider weak electrolyte $AB$.
$AB \rightleftharpoons {A^ + } + {B^ - }$
\[l = 0,{\text{ C 0 0}}\] $ \propto \to {\text{degree }}of{\text{ }}dissociation$
\[t = t,{\text{ }}C - C \propto {\text{ }}C \propto {\text{ }}C \propto \]\[\]
$K = \dfrac{{\left[ {{A^ + }} \right]\left[ {{B^ - }} \right]}}{{\left[ {AB} \right]}} = \dfrac{{\left( {C \propto } \right)\left( {C \propto } \right)}}{{C\left( {1 - \propto } \right)}} = \dfrac{{{ \propto ^2}C}}{{1 - \propto }}$
For weak electrolyte, $ \propto \ll 1$
This implies that $\left( {1 - \propto } \right) \approx 1$
$K = \dfrac{{{ \propto ^2}C}}{{1 - \propto }} = { \propto ^2}C$
So, from this we can say that
$ \propto = \sqrt {\dfrac{K}{C}} $
Thus, it is clear that the degree of dissociation of weak electrolyte is proportional to the inverse square root of the concentration, or the square root of dilution. The concentration of any one ionic species is given by the root of the product of the dissociation constant and concentration of electrolyte.
$\left[ {{A^ + }} \right] = \left[ {{B^ - }} \right] = \propto C = \sqrt {KC} $
Note:
Weak electrolyte, like weak acids and bases partially ionize in solution. On the other hand, strong electrolytes completely or almost completely ionize or dissociate and have many ions.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

The computer jargonwwww stands for Aworld wide web class 12 physics CBSE

State the principle of an ac generator and explain class 12 physics CBSE

