Answer
Verified
377.4k+ views
Hint: Lassaigen's test is a general method for determining the presence of halogens, phosphorus, and sulphur in an organic compound. The organic compound is fused with sodium metal in this process. The ionic compounds formed during fusion are collected in aqueous solution and identified using basic chemical tests.
Complete answer:
The carbon and nitrogen present in the organic compound on fusion with sodium metal gives sodium cyanide $(NaCN)$ soluble in water.
$Na + C + N \to NaCN$
This is converted into sodium ferrocyanide by the addition of sufficient quantities of ferrous sulphate.
$6NaCN + FeS{O_4} \to N{a_4}[Fe{(CN)_6}] + N{a_2}S{O_4}$
The ferric ions generated during the process react with ferrocyanide to form a prussian blue ferric ferrocyanide precipitate.
$N{a_4}[Fe{(CN)_6}] + F{e^{3 + }} \to F{e_4}{[Fe{(CN)_6}]_3}$
Ferric ferrocyanide turns Prussian blue in this reaction, hence it shows positive test for nitrogen with the Lassaigne's solution.
Therefore, the correct option is A) \[F{e_4}{[Fe{(CN)_6}]_3}\]
Note:
As nitrogen reacts with sodium metal, sodium cyanide $(NaCN)$ is formed, which is water soluble. Because of its electropositive nature, sodium is used in Lassaigne's test to transform covalent to ionic form. Its nature is very reactive.
Complete answer:
The carbon and nitrogen present in the organic compound on fusion with sodium metal gives sodium cyanide $(NaCN)$ soluble in water.
$Na + C + N \to NaCN$
This is converted into sodium ferrocyanide by the addition of sufficient quantities of ferrous sulphate.
$6NaCN + FeS{O_4} \to N{a_4}[Fe{(CN)_6}] + N{a_2}S{O_4}$
The ferric ions generated during the process react with ferrocyanide to form a prussian blue ferric ferrocyanide precipitate.
$N{a_4}[Fe{(CN)_6}] + F{e^{3 + }} \to F{e_4}{[Fe{(CN)_6}]_3}$
Ferric ferrocyanide turns Prussian blue in this reaction, hence it shows positive test for nitrogen with the Lassaigne's solution.
Therefore, the correct option is A) \[F{e_4}{[Fe{(CN)_6}]_3}\]
Note:
As nitrogen reacts with sodium metal, sodium cyanide $(NaCN)$ is formed, which is water soluble. Because of its electropositive nature, sodium is used in Lassaigne's test to transform covalent to ionic form. Its nature is very reactive.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE