Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# The atomic of weight of an element is $23$ and its atomic number is $11.$ The number of protons, electrons and neutrons respectively present in the atom of the element are:(A) $11,11,12$ (B) $12,12,11$(C) $11,12,11$ (D)$12,11,12$

Last updated date: 12th Sep 2024
Total views: 419.7k
Views today: 11.19k
Verified
419.7k+ views
Hint:Electrons are the negatively charged particles of an atom. All of the electrons of an atom create a negative charge that balances the positive charge of the protons in the atomic nucleus. Protons are positively charged particles found within an atomic nucleus, a positive electric charge equal in magnitude to that of an electron. Neutrons are about the same mass as a proton but it is just without an electric charge which is present in all atomic nuclei except those of ordinary hydrogen.

So, here in this question the atomic number of the element is $11.$ Hence it contains $11$ protons and $11$ electrons since the element is neutral. Its mass number that is atomic weight is $23$ which is the total number of protons and neutrons together that is known as nucleus. Moreover, the mass number is different for each different isotope of a chemical element.
$\text{Mass Number} = Protons{\text{ }} + {\text{Neutrons}}$
If you want to calculate the no. of neutrons of an atom or element, you can simply subtract the number of protons or atomic number from the mass number. So, the number of neutrons of this element is $(23 - 11)$ that is $12$ neutrons.