# Stopping potential depends onA. Frequency of incident lightB. Intensity of incident lightC. Number of emitted electronsD. Number of incident photons

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Hint: To answer this question we first need to understand the term stopping potential which is also known as cutoff voltage or cutoff potential. The cutoff or stopping potential is the required voltage or potential to stop the removal of the electrons from the given metal surface when the incident energy of the radiation is larger than the work potential of the metal on which the radiation is incident.

$V{\text{ }} = {\text{ }}\dfrac{{\left( {hf{\text{ }} - {\text{ }}\phi } \right)}}{q}{\text{ }}$
where $\phi$ is the work function defined as the amount of energy needed to bind the electrons in the metals, $hf$ is the energy of photons, while $q$ is the charge.
Note: The stopping potential or known as cut off potential is mainly used to determine the kinetic energy that the electrons carry when they are ejected from the metal plate. The product of the charge $q$ on an electron and the stopping voltage $V$ provides the maximum kinetic energy of the electrons that are ejected from the metal plate.