
Solve the following: $\tan (1/2{{\sin }^{-1}}3/4)$
Answer
517.2k+ views
Hint: Revise all the formulas of trigonometry and all the properties of inverse trigonometric functions. The inverse trigonometric functions are the inverse functions of the trigonometric functions for example inverse of sine, cosine, tangent etc.
Complete step by step solution:
We have to solve $\tan (1/2{{\sin }^{-1}}3/4)$ for that let us assume that
$1/2{{\sin }^{-1}}3/4=\theta $
Now by cross multiplication
$1/2{{\sin }^{-1}}3/4=\theta $ becomes
${{\sin }^{-1}}3/4=2\theta $ ---- (1)
Now by multiplying sin on both sides of the equation(1)
$\sin ({{\sin }^{-1}}3/4)=\sin 2\theta $
$\sin 2\theta =3/4$ ---- (2)
Now by using the formula $\sin 2\theta =2\tan \theta /(1+{{\tan }^{2}}\theta )$ on equation (2)
$2\tan \theta /(1+{{\tan }^{2}}\theta )=3/4$
Now by cross multiplication
$2\tan \theta /(1+{{\tan }^{2}}\theta )=3/4$ becomes
$4(2\tan \theta )=3(1+{{\tan }^{2}}\theta )$ ----- (3)
By solving the brackets of equation (3)
$8\tan \theta =3+3{{\tan }^{2}}\theta $
$3{{\tan }^{2}}\theta -8\tan \theta +3=0$ ------- (4)
To find the roots of a quadratic equation we use the formula
$x=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}$
So by using the above formula on equation (4)
$\tan \theta =-(-8)\pm \sqrt{64-(4 \times 3 \times 3}/2 \times 3$
So, $\tan \theta =4\pm \sqrt{7}/3$ ----- (5)
Now by taking tan inverse on both sides of equation (5)
$\theta ={{\tan }^{-1}}\left[ 4\pm \sqrt{7}/3 \right]$
$\tan \theta =4\pm \sqrt{7}/3$
As $\theta =1/2{{\sin }^{-1}}3/4$
So, $\tan \theta =4\pm \sqrt{7}/3$
Since ,
$\begin{align}
& -\pi /2\le {{\sin }^{-1}}3/4\le \pi /2 \\
& -\pi /4\le 1/2{{\sin }^{-1}}3/4\le \pi /4 \\
\end{align}$
Therefore, $\tan (-\pi /4)\le \tan 1/2({{\sin }^{-1}}3/4)\le \tan \pi /4$
$-1\le \tan (1/2{{\sin }^{-1}}3/4)\le 1$
Since, $4+\sqrt{7}/3>1$ so it is ignored
Therefore, $\tan (1/2{{\sin }^{-1}}3/4)=4-\sqrt{7}/3$.
Note:
There is a restriction on $\sin \theta $ i.e. $-\pi /2\le {{\sin }^{-1}}\theta \le \pi /2$. So all the values which are greater than one should be ignored. Always use the correct trigonometric formula to solve a particular equation as using the wrong formula leads towards the wrong answer.
Complete step by step solution:
We have to solve $\tan (1/2{{\sin }^{-1}}3/4)$ for that let us assume that
$1/2{{\sin }^{-1}}3/4=\theta $
Now by cross multiplication
$1/2{{\sin }^{-1}}3/4=\theta $ becomes
${{\sin }^{-1}}3/4=2\theta $ ---- (1)
Now by multiplying sin on both sides of the equation(1)
$\sin ({{\sin }^{-1}}3/4)=\sin 2\theta $
$\sin 2\theta =3/4$ ---- (2)
Now by using the formula $\sin 2\theta =2\tan \theta /(1+{{\tan }^{2}}\theta )$ on equation (2)
$2\tan \theta /(1+{{\tan }^{2}}\theta )=3/4$
Now by cross multiplication
$2\tan \theta /(1+{{\tan }^{2}}\theta )=3/4$ becomes
$4(2\tan \theta )=3(1+{{\tan }^{2}}\theta )$ ----- (3)
By solving the brackets of equation (3)
$8\tan \theta =3+3{{\tan }^{2}}\theta $
$3{{\tan }^{2}}\theta -8\tan \theta +3=0$ ------- (4)
To find the roots of a quadratic equation we use the formula
$x=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}$
So by using the above formula on equation (4)
$\tan \theta =-(-8)\pm \sqrt{64-(4 \times 3 \times 3}/2 \times 3$
So, $\tan \theta =4\pm \sqrt{7}/3$ ----- (5)
Now by taking tan inverse on both sides of equation (5)
$\theta ={{\tan }^{-1}}\left[ 4\pm \sqrt{7}/3 \right]$
$\tan \theta =4\pm \sqrt{7}/3$
As $\theta =1/2{{\sin }^{-1}}3/4$
So, $\tan \theta =4\pm \sqrt{7}/3$
Since ,
$\begin{align}
& -\pi /2\le {{\sin }^{-1}}3/4\le \pi /2 \\
& -\pi /4\le 1/2{{\sin }^{-1}}3/4\le \pi /4 \\
\end{align}$
Therefore, $\tan (-\pi /4)\le \tan 1/2({{\sin }^{-1}}3/4)\le \tan \pi /4$
$-1\le \tan (1/2{{\sin }^{-1}}3/4)\le 1$
Since, $4+\sqrt{7}/3>1$ so it is ignored
Therefore, $\tan (1/2{{\sin }^{-1}}3/4)=4-\sqrt{7}/3$.
Note:
There is a restriction on $\sin \theta $ i.e. $-\pi /2\le {{\sin }^{-1}}\theta \le \pi /2$. So all the values which are greater than one should be ignored. Always use the correct trigonometric formula to solve a particular equation as using the wrong formula leads towards the wrong answer.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

The correct structure of ethylenediaminetetraacetic class 12 chemistry CBSE

Calculate the equivalent resistance between a and b class 12 physics CBSE

How many states of matter are there in total class 12 chemistry CBSE

Which of the following is the best conductor of electricity class 12 physics CBSE

