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# Solubility order of compounds in water is:$A)BeC{L_2} < NaCl < LiCl$$B)NaCl < LiCl < BeC{l_2}$$C)BeC{l_2} < LiCl < NaCl$$D)LiCl < NaCl < BeC{l_2}$

Last updated date: 21st Jul 2024
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Hint: Solubility depends on the charge density and the hydration energy of the compounds. Charge density is the amount of electric charge per unit length, surface area, or volume and Hydration energy increases as the size of the ion decreases and charges on it increases.

Charge density is the amount of electric charge per unit length, surface area, or volume. Volume charge density is the quantity of charge per unit volume, measured in the $SI$system in coulombs per cubic meter, at any point in a volume.
According to the charge density of the given compounds the solubility order is $NaCl < LiCl < BeC{l_2}$
Among $NaCl,LiCl$ and $BeC{l_2}$.$BeC{l_2}$ is the most polar compound, thus its solubility is higher than others.
So, the correct option is $B)NaCl < LiCl < BeC{l_2}$