
Select the correct statement
$A)$$KCl$ can not be used as electrolyte in salt bridges in the case of silver electrodes.
$B)$ cell reaction is spontaneous if emf is positive.
$C)$If the salt bridge is removed, potential falls to zero.
$D)$All of these.
Answer
518.7k+ views
Hint: The purpose of the salt bridge is not to move electrons from the electrolyte, rather to keep up charge balance on the ground that the electrons are moving from one half of the cell to another.
Complete answer:
Let’s see if the given statements are correct or not.
Statement $A)$ is correct.
Because kcl will react with silver and form silver chloride which is insoluble in water.
Statement $B)$ is correct .
As we know, the reaction equation is
$\Delta G = - nF{E^ \circ }$
Here $\Delta G$ is gibbs free energy and tells us if the given reaction is spontaneous or not. If $\Delta G$ is negative then the reaction will be spontaneous and if $\Delta G$ is positive the given reaction will be non spontaneous.
Here $n$ is electron exchange and $F$ is faraday’s constant.
So, if the ${E^ \circ }$ is positive then the $\Delta G$ will be negative so the reaction will be spontaneous.
Statement $C)$ is also correct.
Salt bridge allows the flow of current by completing the circuit. No current will stream and the voltage will drop to zero if the salt bridge is eliminated.
And hence all the given statements are correct.
Note:
Reactions that occur spontaneously have a negative $\Delta G$value, and such reactions are exergonic. The net charge will be zero when the system is at equilibrium because no net change occurs.
Complete answer:
Let’s see if the given statements are correct or not.
Statement $A)$ is correct.
Because kcl will react with silver and form silver chloride which is insoluble in water.
Statement $B)$ is correct .
As we know, the reaction equation is
$\Delta G = - nF{E^ \circ }$
Here $\Delta G$ is gibbs free energy and tells us if the given reaction is spontaneous or not. If $\Delta G$ is negative then the reaction will be spontaneous and if $\Delta G$ is positive the given reaction will be non spontaneous.
Here $n$ is electron exchange and $F$ is faraday’s constant.
So, if the ${E^ \circ }$ is positive then the $\Delta G$ will be negative so the reaction will be spontaneous.
Statement $C)$ is also correct.
Salt bridge allows the flow of current by completing the circuit. No current will stream and the voltage will drop to zero if the salt bridge is eliminated.
And hence all the given statements are correct.
Note:
Reactions that occur spontaneously have a negative $\Delta G$value, and such reactions are exergonic. The net charge will be zero when the system is at equilibrium because no net change occurs.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

The correct structure of ethylenediaminetetraacetic class 12 chemistry CBSE

Calculate the equivalent resistance between a and b class 12 physics CBSE

How many states of matter are there in total class 12 chemistry CBSE

Which of the following is the best conductor of electricity class 12 physics CBSE

