Answer

Verified

435.9k+ views

**Hint:-**: If the object is placed on angle bisector of the two mirrors, then numbers of images formed of the object is given by

\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}} - 1\]

The number of images may be odd or even both.

And if the object is not placed on angle bisector of the two mirrors & the numbers of images formed of the object is odd in numbers , then we have:

\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}}\]

**Complete step-by-step solution**:We want the numbers of images to be five

Case (1) : - If the object is placed at angle bisector of the mirrors

\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}} - 1\]

Numbers of images we want is five

Let the angle between the mirrors is \[\theta \],

Putting the values we get

\[ \Rightarrow 5 = \dfrac{{360^\circ }}{\theta } - 1\]

\[ \Rightarrow 6 = \dfrac{{360^\circ }}{\theta }\]

Solving the equation for \[\theta \], we get

\[ \Rightarrow \theta = \dfrac{{360^\circ }}{6}\]

\[ \Rightarrow \theta = 60^\circ \]

Here no option matches with the result which we have obtained , so we are going for case ( 2 ).

Case (2) : - If the object is not placed at angle bisector of the mirrors & , the numbers of images formed of the object is odd, then we have:

\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}}\]

Numbers of images we want is five

Let the angle between the mirrors is \[\theta \],

Putting the values we get

\[ \Rightarrow 5 = \dfrac{{360^\circ }}{\theta }\]

Solving the equation for \[\theta \], we get

\[ \Rightarrow \theta = \dfrac{{360^\circ }}{5}\]

\[ \Rightarrow \theta = 72^\circ \]

Here to get five images of a single object , one should have a plane mirror at an angle of \[72^\circ \].

Hence option ( B ) is the correct answer.

**Note:-**

If we want to find an infinite number of images of an object, place both of the mirrors parallel, that means the angle between them is ( \[\theta = 0^\circ \]).

If a plane mirror is placed in front of an object and the object approaches the mirror with velocity ( v ), then the velocity of its image will appear to be ( 2v ) in the mirror.

Recently Updated Pages

How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE

Mark and label the given geoinformation on the outline class 11 social science CBSE

When people say No pun intended what does that mea class 8 english CBSE

Name the states which share their boundary with Indias class 9 social science CBSE

Give an account of the Northern Plains of India class 9 social science CBSE

Change the following sentences into negative and interrogative class 10 english CBSE

Trending doubts

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

Difference Between Plant Cell and Animal Cell

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

At which age domestication of animals started A Neolithic class 11 social science CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Summary of the poem Where the Mind is Without Fear class 8 english CBSE

One cusec is equal to how many liters class 8 maths CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Change the following sentences into negative and interrogative class 10 english CBSE