Answer
414.9k+ views
Hint:-: If the object is placed on angle bisector of the two mirrors, then numbers of images formed of the object is given by
\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}} - 1\]
The number of images may be odd or even both.
And if the object is not placed on angle bisector of the two mirrors & the numbers of images formed of the object is odd in numbers , then we have:
\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}}\]
Complete step-by-step solution:We want the numbers of images to be five
Case (1) : - If the object is placed at angle bisector of the mirrors
\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}} - 1\]
Numbers of images we want is five
Let the angle between the mirrors is \[\theta \],
Putting the values we get
\[ \Rightarrow 5 = \dfrac{{360^\circ }}{\theta } - 1\]
\[ \Rightarrow 6 = \dfrac{{360^\circ }}{\theta }\]
Solving the equation for \[\theta \], we get
\[ \Rightarrow \theta = \dfrac{{360^\circ }}{6}\]
\[ \Rightarrow \theta = 60^\circ \]
Here no option matches with the result which we have obtained , so we are going for case ( 2 ).
Case (2) : - If the object is not placed at angle bisector of the mirrors & , the numbers of images formed of the object is odd, then we have:
\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}}\]
Numbers of images we want is five
Let the angle between the mirrors is \[\theta \],
Putting the values we get
\[ \Rightarrow 5 = \dfrac{{360^\circ }}{\theta }\]
Solving the equation for \[\theta \], we get
\[ \Rightarrow \theta = \dfrac{{360^\circ }}{5}\]
\[ \Rightarrow \theta = 72^\circ \]
Here to get five images of a single object , one should have a plane mirror at an angle of \[72^\circ \].
Hence option ( B ) is the correct answer.
Note:-
If we want to find an infinite number of images of an object, place both of the mirrors parallel, that means the angle between them is ( \[\theta = 0^\circ \]).
If a plane mirror is placed in front of an object and the object approaches the mirror with velocity ( v ), then the velocity of its image will appear to be ( 2v ) in the mirror.
\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}} - 1\]
The number of images may be odd or even both.
And if the object is not placed on angle bisector of the two mirrors & the numbers of images formed of the object is odd in numbers , then we have:
\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}}\]
Complete step-by-step solution:We want the numbers of images to be five
Case (1) : - If the object is placed at angle bisector of the mirrors
\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}} - 1\]
Numbers of images we want is five
Let the angle between the mirrors is \[\theta \],
Putting the values we get
\[ \Rightarrow 5 = \dfrac{{360^\circ }}{\theta } - 1\]
\[ \Rightarrow 6 = \dfrac{{360^\circ }}{\theta }\]
Solving the equation for \[\theta \], we get
\[ \Rightarrow \theta = \dfrac{{360^\circ }}{6}\]
\[ \Rightarrow \theta = 60^\circ \]
Here no option matches with the result which we have obtained , so we are going for case ( 2 ).
Case (2) : - If the object is not placed at angle bisector of the mirrors & , the numbers of images formed of the object is odd, then we have:
\[number\;of\,images = \dfrac{{360^\circ }}{{angle\;between\;mirrors}}\]
Numbers of images we want is five
Let the angle between the mirrors is \[\theta \],
Putting the values we get
\[ \Rightarrow 5 = \dfrac{{360^\circ }}{\theta }\]
Solving the equation for \[\theta \], we get
\[ \Rightarrow \theta = \dfrac{{360^\circ }}{5}\]
\[ \Rightarrow \theta = 72^\circ \]
Here to get five images of a single object , one should have a plane mirror at an angle of \[72^\circ \].
Hence option ( B ) is the correct answer.
Note:-
If we want to find an infinite number of images of an object, place both of the mirrors parallel, that means the angle between them is ( \[\theta = 0^\circ \]).
If a plane mirror is placed in front of an object and the object approaches the mirror with velocity ( v ), then the velocity of its image will appear to be ( 2v ) in the mirror.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)