# Propane $\to$ 2-IodopropaneBest reagent for the above conversion is:(a)- ${{I}_{2}}/hv$ (b)- NaI / acetone(c)- ${{F}_{2}}/hv$, NaI / acetone(d)- $B{{r}_{2}}/hv$, NaI / acetone

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Hint: When alkane is treated with halogen, sunlight is used as a catalyst for the addition of halogen. But the fluorine and iodine cannot be directly attached to the alkane by using sunlight.

$C{{H}_{3}}-C{{H}_{2}}-C{{H}_{3}}$
So the correct reagents used are $B{{r}_{2}}/hv$, NaI / acetone.
Therefore, the correct answer is an option (d)- $B{{r}_{2}}/hv$, NaI / acetone.