# Normality of 2% ${{\text{H}}_{2}}\text{S}{{\text{O}}_{4}}$ solution by volume is nearly:

A. 2

B. 4

C. 0.2

D. 0.4

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**Hint:**The concentration of a solution can be measured with the help of normality. Normality is the ratio of a number of grams equivalent by volume of solution in litre. It can measure the number of ions in the precipitation reaction.

**Complete answer:**

-Here, 2% of sulphuric acid means that 2 gram of sulphuric acid is present or dissolved in the 100ml of solution.

-That means the volume of a solution is 100ml.

-Now, to calculate the normality firstly we have to calculate the number of gram equivalent mass of ${{\text{H}}_{2}}\text{S}{{\text{O}}_{4}}$.

-The formula is weighted by gram equivalent mass of ${{\text{H}}_{2}}\text{S}{{\text{O}}_{4}}$.

-The mass of the ${{\text{H}}_{2}}\text{S}{{\text{O}}_{4}}$is given that is 2 gram and the gram equivalent will be calculated by the division of molar mass by n-factor i.e. $49/1$=49.

-So, the gram equivalent mass of ${{\text{H}}_{2}}\text{S}{{\text{O}}_{4}}$ will be $\dfrac{2}{49}$.

-Now, we will calculate normality by using the formula i.e. $\dfrac{\text{Equivalent }\cdot \text{ 1000}}{\text{Volume of solution}}$

-Here, the value of equivalent and volume of solution will be 2/49 and 100 respectively.

The value of normality will be:

$\dfrac{2\ \cdot \text{ 1000}}{49\text{ }\cdot \text{ 100}}\,\text{= 0}\text{.4}$

**Therefore, option C is the correct answer.**

**Note:**Normality is used for the acid and bases mostly. The normality is also related to the molarity o.r. normality is equal to the product of n and molarity where n is equal to the number of hydrogen ions in the acid or no. of hydroxyl ions in the base or n-factor.