
How long would it take a radio wave of frequency \[6 \times {10^3}\sec \] to travel from Mars to the Earth, a distance of \[8 \times {10^7}km\]?
Answer
503.1k+ views
Hint: A radio wave is an electromagnetic wave. We know that the speed of all electromagnetic waves in a vacuum is the same, irrespective of their frequency. Again, the speed of an electromagnetic wave in a vacuum is the same as that of light, i.e. \[3 \times {10^8}\dfrac{m}{s}\]
The distance between Earth and Mars is given. Therefore we can find the time taken to cover this distance with a speed of\[3 \times {10^8}\dfrac{m}{s}\].
Formula used:
\[time = \dfrac{{dis\tan ce}}{{velocity}}\]
Distance = \[8 \times {10^7}km\]
Velocity = \[3 \times {10^8}\dfrac{m}{s}\]
Complete step-by-step solution:
Given that, a radio wave travels from Mars to Earth.
The radio wave is an electromagnetic wave. We know that the speed of all electromagnetic waves in a vacuum is the same, irrespective of their frequency.
The speed of an electromagnetic wave in a vacuum is the same as that of light, i.e. \[3 \times {10^8}\dfrac{m}{s}\]
The distance of Mars from Earth is given by\[8 \times {10^7}km\], i.e. \[8 \times {10^{10}}m\]. \[(1km{\text{ }} = {\text{ }}1000{\text{ }}m)\]
Therefore, the total time taken to travel is given by:
\[time = \dfrac{{dis\tan ce}}{{velocity}}\]
\[ \Rightarrow t = \dfrac{{8 \times {{10}^{10}}}}{{3 \times {{10}^8}}}\]
\[ \Rightarrow t = \dfrac{{800}}{3}\]
\[ \Rightarrow t = 266.67\sec \]
\[ \Rightarrow t = \dfrac{{266.67}}{{60}} = 4.44\min \]
Hence, it will take the radio wave approximately \[266.67{\text{ }}seconds\] or \[4.44{\text{ }}minutes\] to travel from Mars to Earth.
Note: From the given question, the distance between Earth and Mars is given in kilometers. Change the unit to meters and proceed. We know that one kilometer is equal to \[{10^3}\]meter and One minute is equal to \[60\] seconds.
The distance between Earth and Mars is given. Therefore we can find the time taken to cover this distance with a speed of\[3 \times {10^8}\dfrac{m}{s}\].
Formula used:
\[time = \dfrac{{dis\tan ce}}{{velocity}}\]
Distance = \[8 \times {10^7}km\]
Velocity = \[3 \times {10^8}\dfrac{m}{s}\]
Complete step-by-step solution:
Given that, a radio wave travels from Mars to Earth.
The radio wave is an electromagnetic wave. We know that the speed of all electromagnetic waves in a vacuum is the same, irrespective of their frequency.
The speed of an electromagnetic wave in a vacuum is the same as that of light, i.e. \[3 \times {10^8}\dfrac{m}{s}\]
The distance of Mars from Earth is given by\[8 \times {10^7}km\], i.e. \[8 \times {10^{10}}m\]. \[(1km{\text{ }} = {\text{ }}1000{\text{ }}m)\]
Therefore, the total time taken to travel is given by:
\[time = \dfrac{{dis\tan ce}}{{velocity}}\]
\[ \Rightarrow t = \dfrac{{8 \times {{10}^{10}}}}{{3 \times {{10}^8}}}\]
\[ \Rightarrow t = \dfrac{{800}}{3}\]
\[ \Rightarrow t = 266.67\sec \]
\[ \Rightarrow t = \dfrac{{266.67}}{{60}} = 4.44\min \]
Hence, it will take the radio wave approximately \[266.67{\text{ }}seconds\] or \[4.44{\text{ }}minutes\] to travel from Mars to Earth.
Note: From the given question, the distance between Earth and Mars is given in kilometers. Change the unit to meters and proceed. We know that one kilometer is equal to \[{10^3}\]meter and One minute is equal to \[60\] seconds.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

