Question

How many ions will be produced in solution from one molecule of chloropentammine cobalt (III) chloride
A. 1
B. 2
C. 3
D. 4

Answer 1

Hint: As the ions present in the coordination sphere do not dissociate and instead stay together in an aqueous solution, coordination compounds do not entirely break down into all of their ions. Only the substances that are joined to the complex produce ions.

Complete answer:Salts can be divided into two categories, simple salt, and mixed salt, based on how many different types of ions they contain. Simple salts only include one kind of each cation and anion. For instance, KCl, NaCl, and \[MgC{{l}_{2}}\].

More than one type of cation or anion can be found in mixed salt. Additionally, there are two forms of mixed salts: coordination complex and double salt. Water entirely dissociates into its ion components after mixing with double salts. For instance, Mohr salt \[FeS{{O}_{4}}.{{\left( N{{H}_{4}} \right)}_{2}}S{{O}_{4}}.6{{H}_{2}}O\]and Cernalite\[KCl.MgC{{l}_{2}}.6{{H}_{2}}O\]. Water does not entirely separate coordination compounds into their cationic and anionic parts.

The formula for chloropentammine cobalt (III) chloride is \[~[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\]. We’ll see the number of ions in the solution. Therefore, we can see the reaction as follows:
\[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\to {{[Co{{(N{{H}_{3}})}_{5}}Cl]}^{2+}}+2C{{l}^{-}}\]
So on dissociation of one mole of \[~[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\]we get 1 ion of\[~{{[Co{{(N{{H}_{3}})}_{5}}Cl]}^{2+}}\]and 2 ions of $C{{l}^{-}}$ions.

Hence, the correct option is C. 3

Note:When naming a coordination complex, the cation is written first, followed by the anion. The center metal atom is named with its oxidation number in roman numerals after the ligands are named in alphabetical order during the naming of the coordination sphere.