Courses
Courses for Kids
Free study material
Free LIVE classes
More
LIVE
Join Vedantu’s FREE Mastercalss

Integrate the following with respect to x:
$\int {\dfrac{1}{{2x + 3}}dx} $.

Answer
VerifiedVerified
363.3k+ views
Hint: Simple substitution of the denominator to some variable will help simplifying the integral and reducing it to a standard integral. Use this technique to evaluate this integral.

Complete step-by-step answer:
Let $I = {\text{ }}\int {\dfrac{1}{{2x + 3}}dx} $……………………… (1)
Let 2x+3 = p…………………. (2)

Now, differentiate both the sides of equation (2) we get,
$ \Rightarrow 2dx = dp$………………………… (3)

Make this substitution back into the main integral$I$, substituting (3) in equation (1) we get
$ \Rightarrow I = {\text{ }}\dfrac{1}{2}\int {\dfrac{1}{p}dp} $…………………. (4)

Now, we know that the standard integral of,\[\int {\dfrac{1}{x}dx = \log x} \] ……………… (5)
So the value of equation (4) will be, using above equation (5) we get,
$I = \dfrac{1}{2}\log p + c$

Now, let’s substitute the value of p back into the above integral we get
$I = \dfrac{1}{2}\log \left( {2x + 3} \right) + c$ Using equation (2)

Note: Whenever we face such problems always try and simplify the integral via method of substitution. This will help simplifying the integral into a standard from. Don’t forget to substitute back the variable assumed and take the solution back to the main variable provided in question. The constant of integration is also to be taken care of in exams.
Last updated date: 01st Oct 2023
Total views: 363.3k
Views today: 4.63k