In the reaction $C{H_3}C{H_2}CH = C{H_2}\xrightarrow[{NaB{D_4}}]{{Hg{{\left( {OAc} \right)}_2}.{H_2}O}}$ in this reaction the product is.
A) $C{H_3}C{H_2}CHOHC{H_2}D$
B) $C{H_3}C{H_2}CHDC{H_2}OH$
C) $C{H_3}C{H_2}CD\left( {OH} \right)C{H_3}$
D) $C{H_3}C{H_2}C{D_2}C{H_2}OH$
Answer
603.3k+ views
Hint:We know that Oxymercuration- Demercuration reaction undergoes Markovnikov addition across the alkene double bond . A reaction in which an alkene is reacted with a Hg^{2+} salt and an oxygen nucleophile (water or an alcohol), to form an organomercury intermediate. The intermediate's carbon-mercury bond is then converted to a carbon-hydrogen bond by treatment with $NaBH_4$.
Complete step by step answer:
An organic reaction which changes an alkene into alcohol is called an Oxymercuration reaction. Oxymercuration undergoes electrophilic addition reaction, In this reaction the alkene reacts with mercuric acetate \[\left( {{\text{AcOHgOAc}}} \right)\] in aqueous solution to give acetyl mercuri \[\left( {{\text{HgOAc}}} \right)\] group and a hydroxy \[\left( {{\text{OH}}} \right)\] group across the double bond. The reaction follows Markovnikov's rule addition.
We can write the complete chemical equation as,
$C{H_3}C{H_2}CH = C{H_2}\xrightarrow[{NaB{D_4}}]{{Hg{{\left( {OAc} \right)}_2}.{H_2}O}}$${\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{CHOHC}}{{\text{H}}_{\text{2}}}{\text{D}}$
Therefore, the option A is correct.
Additional Note:
The process in which the hydrogen boron bond is added to a double bond between either carbon and carbon or carbon and nitrogen is called Hydroboration reaction. Hydroboration can also be done on a carbon-carbon triple bond. This method is useful in the synthesis of some organic compounds. Organoborane compounds are chemical compounds which have carbon-boron bonds and are derivatives of borane which are synthesized by Hydroboration method. These organoborane can be reacted with some reagents to give alkyl halides, alcohols, and amines which are quite useful. The oxidation of the organoborane in the presence of hydrogen peroxide yields alcohols.
Note: We know that Markovnikov's rule:
The regioselectivity of electrophilic addition reactions of alkenes and alkynes is determined by Markovnikov's rule. It states that, in halogen adds to an unsymmetrical alkene, the atom within the hydrogen halide forms a bond with the doubly bonded atom within the alkene, bearing the greater number of hydrogen atoms.
Complete step by step answer:
An organic reaction which changes an alkene into alcohol is called an Oxymercuration reaction. Oxymercuration undergoes electrophilic addition reaction, In this reaction the alkene reacts with mercuric acetate \[\left( {{\text{AcOHgOAc}}} \right)\] in aqueous solution to give acetyl mercuri \[\left( {{\text{HgOAc}}} \right)\] group and a hydroxy \[\left( {{\text{OH}}} \right)\] group across the double bond. The reaction follows Markovnikov's rule addition.
We can write the complete chemical equation as,
$C{H_3}C{H_2}CH = C{H_2}\xrightarrow[{NaB{D_4}}]{{Hg{{\left( {OAc} \right)}_2}.{H_2}O}}$${\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{CHOHC}}{{\text{H}}_{\text{2}}}{\text{D}}$
Therefore, the option A is correct.
Additional Note:
The process in which the hydrogen boron bond is added to a double bond between either carbon and carbon or carbon and nitrogen is called Hydroboration reaction. Hydroboration can also be done on a carbon-carbon triple bond. This method is useful in the synthesis of some organic compounds. Organoborane compounds are chemical compounds which have carbon-boron bonds and are derivatives of borane which are synthesized by Hydroboration method. These organoborane can be reacted with some reagents to give alkyl halides, alcohols, and amines which are quite useful. The oxidation of the organoborane in the presence of hydrogen peroxide yields alcohols.
Note: We know that Markovnikov's rule:
The regioselectivity of electrophilic addition reactions of alkenes and alkynes is determined by Markovnikov's rule. It states that, in halogen adds to an unsymmetrical alkene, the atom within the hydrogen halide forms a bond with the doubly bonded atom within the alkene, bearing the greater number of hydrogen atoms.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

Why should a magnesium ribbon be cleaned before burning class 12 chemistry CBSE

