Question

In the climax of a movie, the hero jumps from a helicopter and the villain chasing the hero also jumps at the same time from the same level. After sometime when we're at the same horizontal level, the villain fires bullets horizontally towards the hero. Both were falling with constant acceleration \[2m/{{s}^{2}}\], because of the parachute. Assuming the hero to be within the range of the bullet, and air resistance force on the bullet is negligible. Which of the following is correct?
A. Bullet will hit the hero
B. Bullet will pass above the hero
C.Bullet will pass below the hero
D.If both were falling with constant acceleration $g$ instead of $2 \dfrac{m}{s^{2}}$

Answer 1

Hint: An object that moves only because of gravity's action is said to be free falling and Newton's second law of motion describes its motion. At sea level on Earth, the acceleration is constant and equal to gravitational acceleration g, which is 9.8 meters per square second. Here we have to calculate the net acceleration of the two bodies under the certain condition of freefall.

Complete Step-by-Step solution:
As the villain and hero both falling with the same acceleration means both the feel relatively at rest to each other and when the bullet fired both of them at same height and the downward acceleration on the villain and bullet.
\[a=(g-g)m/{{s}^{2}}\]
\[a=0m/{{s}^{2}}\]

Freefall is a special case of constantly accelerating motion, because acceleration is always constant and downward due to gravity. This is true even when an object has zero velocity or is thrown upward. Gravity acceleration is always constant and downward, but it changes the direction and magnitude of velocity.

\[\therefore \] Bullet will hit the hero.

Therefore, the correct option is (A).

Note:
An object that moves only because of gravity's action is said to be free falling and Newton's second law of motion describes its motion. An accelerating object will sometimes change its velocity every second by the same amount. This is referred to as a steady acceleration as every second the velocity changes by a constant amount. It is not necessary to confuse an object with constant acceleration with an object with constant velocity.