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**Hint:**An electric circuit and each component of the circuit are known as an element. The given circuit is connected from the resistance values $20\Omega $ and$5\Omega $.

The ideal diodes are connected from the ${S_{1{\text{ }}}}{\text{and }}{S_2}$ switches.

**Complete step by step answer:**

It is given ${V_A} > {V_B},$so current flows from A to B.

From the below figure when ${S_1}$ is open and ${S_2}$is closed

-The diode at ${S_2}$passes current only from D to C else zero current.

-If the current passes through the diode the voltage will be equal to D and C.

Let us assume that the D and C voltages are equal. Now we can short the ${S_2}$part.

Now in the equivalent circuit as$20\Omega > 5\Omega $current flows from D to C.

So it is satisfying the diode property.

Our circuit equivalent circuit will be the above circuit.

So the equivalent resistance $ = 2 \times \dfrac{1}{{\left( {\dfrac{1}{{20}} + \dfrac{1}{5}} \right)}}\Omega $

Here we have to take an LCM on the denominator term we get

$ = 2 \times \dfrac{1}{{\left( {\dfrac{{1 + 4}}{{20}}} \right)}}\Omega $

Let us add the term we get

$ = 2 \times \dfrac{1}{{\left( {\dfrac{5}{{20}}} \right)}}\Omega $

On dividing the term we get

$ = 2 \times \dfrac{1}{{\left( {\dfrac{1}{4}} \right)}}\Omega $

Taking reciprocal of the numerator term and multiply it we get,

$ = 8\Omega $

Now,${S_1}$ is closed and ${S_2}$is open

-The diode at ${S_1}$passes current only from C to D or else zero current.

- If current passes through the diode the voltage will be equal to D and C.

-Let us assume that the D and C voltage is equal. Now in the equivalent circuit as $20\Omega {\text{ > }}5\Omega $current has to flow from D to C. From D to C current does not allow. So our assumption is wrong.

We have to treat ${S_1}$as open.

The equivalent resistance is $ = \dfrac{{20 + 5}}{2}\Omega $

On adding the numerator term we get

$ = \dfrac{{25}}{2}\Omega $

Let us divide the term we get

$ = 12.5\Omega $

**Additional information:**

Potential difference, when the current flows between two points A and B of an electric circuit.

Where the aggregate resistance connected either in parallel or series is calculated, it is called equivalent resistance. Essentially, either in Series or Parallel is designed in the circuit

**Note:**A diode that acts like a perfect conductor, ideal diodes, when voltage is applied forward biased and like a perfect insulator, when voltage is applied reverse biased.

So the anode to the cathode when the positive voltage is applied across, the diode conducts forward current instantly.

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