# If aniline is treated with conc. ${H_2}S{O_4}$ and heated at ${200^\circ }C$, what would be the product?A) Anilinium sulphateB) Benzenesulfonic acidC) m-aminobenzenesulfonic acidD) sulphanilic acid

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Hint:As we know that aromatic amines undergo typical electrophilic substitution reactions of aromatic ring and the amine group present on the ring is electron releasing and strongly ring activating and thereby increasing the electron density on ortho and para positions.

We also know that aniline undergoes sulfonation reaction where it reacts with concentrated sulphuric acid resulting in the formation of anilinium hydrogen sulphate as an intermediate which on further heating with sulphuric acid at a temperature of about $453 - 473K$ or simply at ${200^\circ }C$, produces a para-aminobenzene sulfonic acid which is commonly called as sulphanilic acid as the major product where $- S{O_3}H$ group gets attached at the para position of the benzene ring. We can show this equation with the help of a chemical reaction as given below:
Note:Always remember that $- N{H_2}$ group present on the benzene ring is electron releasing and thus ortho (-o) and para (-p) directing towards electrophilic aromatic substitution reaction.