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Hint: In order to solve this problem one must know the formula ${\text{|adjA| = |A}}{{\text{|}}^{{\text{n - 1}}}}$ where n is the order of the matrix. Using this will solve our problem and we will get the right value of K.

Complete step-by-step answer:

The given equation is ${\text{|adjA| = |A}}{{\text{|}}^{\text{K}}}$ A is a matrix of order 3.

And we know that if A is a matrix of order 3 then ${\text{|adjA| = |A}}{{\text{|}}^{{\text{n - 1}}}}$ where n is the order of the matrix.

Here order is 3 so n = 3.

Then we can say that ${\text{|adjA| = |A}}{{\text{|}}^{\text{K}}}{\text{ = |A}}{{\text{|}}^{{\text{n - 1}}}} = {\text{|A}}{{\text{|}}^{3 - 1}}{\text{ = |A}}{{\text{|}}^2}$

Then we get ${\text{|A}}{{\text{|}}^{\text{K}}} = {\text{|A}}{{\text{|}}^2}$

Hence, the value of K is 2.

Note: Whenever you face such types of problems then you need to know the most important formula of matrices and determinants like ${\text{|adjA| = |A}}{{\text{|}}^{{\text{n - 1}}}}$ where n is the order of the matrix.

Complete step-by-step answer:

The given equation is ${\text{|adjA| = |A}}{{\text{|}}^{\text{K}}}$ A is a matrix of order 3.

And we know that if A is a matrix of order 3 then ${\text{|adjA| = |A}}{{\text{|}}^{{\text{n - 1}}}}$ where n is the order of the matrix.

Here order is 3 so n = 3.

Then we can say that ${\text{|adjA| = |A}}{{\text{|}}^{\text{K}}}{\text{ = |A}}{{\text{|}}^{{\text{n - 1}}}} = {\text{|A}}{{\text{|}}^{3 - 1}}{\text{ = |A}}{{\text{|}}^2}$

Then we get ${\text{|A}}{{\text{|}}^{\text{K}}} = {\text{|A}}{{\text{|}}^2}$

Hence, the value of K is 2.

Note: Whenever you face such types of problems then you need to know the most important formula of matrices and determinants like ${\text{|adjA| = |A}}{{\text{|}}^{{\text{n - 1}}}}$ where n is the order of the matrix.

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