Answer
Verified
452.4k+ views
Hint: In this type of question, where we have to find the square root of a complex number, the standard way is to assume that the square root of the given complex number is a new complex number which is x+iy and then square both sides. Solve the equation formed to get the value of the square root of the given complex number.
Complete step-by-step answer:
In the question, it is given a complex number -8+6i.
Because the number given is a complex number, so, we cannot directly find the value of the square root.
Let us first assume that the square root of a given complex number is x+iy.
$\therefore $ According to question, we can write:
$\sqrt { - 8 + 6i} = ({\text{x + iy)}}$ .
On squaring both side, we get:
$ - 8 + 6i = {({\text{x + iy)}}^2}$ .
On solving the above equation, we get:
$ - 8 + 6i = {{\text{x}}^2}{\text{ - }}{{\text{y}}^2} + 2i{\text{xy}}$ .
Now, equating the real and imaginary part on both side, we get:
$ - 8 = {{\text{x}}^2}{\text{ - }}{{\text{y}}^2}$ ------ (1)
And
$
2{\text{xy = 6}} \\
\Rightarrow {\text{xy = }}\dfrac{6}{2} = 3 \\
$ ----------------- (2)
We know that ${({\text{a + b)}}^2} = {\left( {{\text{a - b}}} \right)^2} + 4{\text{ab}}$ .
Therefore, we can write:
${({{\text{x}}^2}{\text{ + }}{{\text{y}}^2})^2} = {({{\text{x}}^2}{\text{ - }}{{\text{y}}^2})^2} + 4{\left( {{\text{xy}}} \right)^2}$ .
Putting the values from Equation 1 and 2, we get:
$
{({{\text{x}}^2}{\text{ + }}{{\text{y}}^2})^2} = {( - 8)^2} + 4{\left( 3 \right)^2} = 64 + 36 = 100 \\
\Rightarrow ({{\text{x}}^2} + {{\text{y}}^2}) = \pm \sqrt {100} = \pm 10 \\
$
$\because $ x and y are real numbers. So, the sum of squares of x and y can never be negative.
So, the only solution is:
$({{\text{x}}^2} + {{\text{y}}^2}) = 10$ -----------(3)
On adding equation 1 and 3, we get:
$
2{{\text{x}}^2} = 2 \\
\Rightarrow {{\text{x}}^2} = \dfrac{2}{2} = 1 \\
\Rightarrow {\text{x}} = \pm \sqrt 1 = \pm 1 \\
$
Putting the value of x in equation 3, we get:
$
{1^2} + {{\text{y}}^2} = 10 \\
\Rightarrow {{\text{y}}^2} = 10 - 1 = 9 \\
\Rightarrow {\text{y = }} \pm \sqrt 9 = \pm 3. \\
$
But, from equation 2:
${\text{xy = 3}}$ .
Since the product of x and y is positive. So, x and y can be either both positive or can both be negative.
Therefore, the square root of $ - 8 + 6i = \pm (1 + 3i)$ i.e. (1+3i) and (-1-3i).
So, option A is correct.
Note: In this type of question the first step is to assume the square root of a given complex number as an unknown complex number and then square both sides to get an equation in x and y .After this use the algebraic identities to find the value of unknown parameter x and y. One point to be noted is that not all the value of x and y will give the required complex number. We have to take only those values which satisfy the remaining equation which in this case is xy=3.
Complete step-by-step answer:
In the question, it is given a complex number -8+6i.
Because the number given is a complex number, so, we cannot directly find the value of the square root.
Let us first assume that the square root of a given complex number is x+iy.
$\therefore $ According to question, we can write:
$\sqrt { - 8 + 6i} = ({\text{x + iy)}}$ .
On squaring both side, we get:
$ - 8 + 6i = {({\text{x + iy)}}^2}$ .
On solving the above equation, we get:
$ - 8 + 6i = {{\text{x}}^2}{\text{ - }}{{\text{y}}^2} + 2i{\text{xy}}$ .
Now, equating the real and imaginary part on both side, we get:
$ - 8 = {{\text{x}}^2}{\text{ - }}{{\text{y}}^2}$ ------ (1)
And
$
2{\text{xy = 6}} \\
\Rightarrow {\text{xy = }}\dfrac{6}{2} = 3 \\
$ ----------------- (2)
We know that ${({\text{a + b)}}^2} = {\left( {{\text{a - b}}} \right)^2} + 4{\text{ab}}$ .
Therefore, we can write:
${({{\text{x}}^2}{\text{ + }}{{\text{y}}^2})^2} = {({{\text{x}}^2}{\text{ - }}{{\text{y}}^2})^2} + 4{\left( {{\text{xy}}} \right)^2}$ .
Putting the values from Equation 1 and 2, we get:
$
{({{\text{x}}^2}{\text{ + }}{{\text{y}}^2})^2} = {( - 8)^2} + 4{\left( 3 \right)^2} = 64 + 36 = 100 \\
\Rightarrow ({{\text{x}}^2} + {{\text{y}}^2}) = \pm \sqrt {100} = \pm 10 \\
$
$\because $ x and y are real numbers. So, the sum of squares of x and y can never be negative.
So, the only solution is:
$({{\text{x}}^2} + {{\text{y}}^2}) = 10$ -----------(3)
On adding equation 1 and 3, we get:
$
2{{\text{x}}^2} = 2 \\
\Rightarrow {{\text{x}}^2} = \dfrac{2}{2} = 1 \\
\Rightarrow {\text{x}} = \pm \sqrt 1 = \pm 1 \\
$
Putting the value of x in equation 3, we get:
$
{1^2} + {{\text{y}}^2} = 10 \\
\Rightarrow {{\text{y}}^2} = 10 - 1 = 9 \\
\Rightarrow {\text{y = }} \pm \sqrt 9 = \pm 3. \\
$
But, from equation 2:
${\text{xy = 3}}$ .
Since the product of x and y is positive. So, x and y can be either both positive or can both be negative.
Therefore, the square root of $ - 8 + 6i = \pm (1 + 3i)$ i.e. (1+3i) and (-1-3i).
So, option A is correct.
Note: In this type of question the first step is to assume the square root of a given complex number as an unknown complex number and then square both sides to get an equation in x and y .After this use the algebraic identities to find the value of unknown parameter x and y. One point to be noted is that not all the value of x and y will give the required complex number. We have to take only those values which satisfy the remaining equation which in this case is xy=3.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Why Are Noble Gases NonReactive class 11 chemistry CBSE
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
At which age domestication of animals started A Neolithic class 11 social science CBSE
Which are the Top 10 Largest Countries of the World?
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Write a letter to the principal requesting him to grant class 10 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE