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**Hint:**As per the given information in the question, abscissa means x- axis’s point so x \[{\text{ = 1}}\]. We can calculate the slope of the curve using \[\dfrac{{{\text{dy}}}}{{{\text{dx}}}}\] method. And also remember the information that tangent and normal are perpendicular to each other. And finally, we need to write the equation of the line using point-slope form.

**Complete step by step solution:**Given curve \[{\text{3}}{{\text{x}}^{\text{3}}}{\text{ - 4x + 7}}\],

First of all calculating the coordinates of the point that can be given as ,

\[

{\text{x = 1,}} \\

{\text{y = 3}}{{\text{x}}^{\text{3}}}{\text{ - 4x + 7}} \\

{\text{ = 3 - 4 + 7}} \\

{\text{ = 6}} \\

{\text{(x,y) = (1,6)}} \\

\]

Now, calculating the slope of tangent to the given curve at the designated coordinate,

\[

{{\text{(}}\dfrac{{{\text{dy}}}}{{{\text{dx}}}}{\text{)}}_{{\text{x = 1}}}}{\text{ = (9}}{{\text{x}}^{\text{2}}}{\text{ - 4}}{{\text{)}}_{{\text{x = 1}}}} \\

{\text{ = 9(1) - 4}} \\

{\text{m = 5}} \\

\]

Hence as we know the slope and point so we can write the equation of line as ,

\[

{\text{y - }}{{\text{y}}_{\text{1}}}{\text{ = m(x - }}{{\text{x}}_{\text{1}}}{\text{)}} \\

\Rightarrow {\text{y - 6 = 5(x - 1)}} \\

\Rightarrow {\text{y - 6 = 5x - 5}} \\

\Rightarrow {\text{5x - y + 1 = 0}} \\

\]

Above is the equation of tangent and now using the perpendicular condition to calculate the slope of normal’s line.

\[

{{\text{m}}_1}{m_2} = - 1 \\

{\text{as, }}{m_1} = 5 \\

\Rightarrow {m_2} = \dfrac{{ - 1}}{5} \\

\]

Now, again using point slope method to write the equation of normal,

\[

{\text{y - }}{{\text{y}}_{\text{1}}}{\text{ = m(x - }}{{\text{x}}_{\text{1}}}{\text{)}} \\

\Rightarrow {\text{y - 6 = }}\dfrac{{ - 1}}{5}{\text{(x - 1)}} \\

\Rightarrow {\text{5y - 30 = - x + 1}} \\

\Rightarrow {\text{5y + x = 31 = 0}} \\

\]

**Hence , \[{\text{5y - 30 = - x + 1}}\] is equation of normal.**

**Note:**In common usage, the abscissa refers to the horizontal (x) axis and the ordinate refers to the vertical (y) axis of a standard two-dimensional graph.

A tangent to a curve is a line that touches the curve at one point and has the same slope as the curve at that point. A normal to a curve is a line perpendicular to a tangent to the curve.

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