Note: The measure of 5 radians lie in the fourth quadrant. We have $$\cos^{-1} ({\cos }\theta ) = \theta $$ only for $\left( {0 \leqslant \theta \leqslant \pi } \right)$ So we converted that as $\cos 5 = cos\left( {2\pi - 5} \right)$. The value of $\left( {2\pi - 5} \right)$ is less than $\pi $.
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