Answer
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Hint: To increase the amplitude of the alternating current, we use the common emitter configuration of the transistor. Express the expression for the voltage gain in terms of resistance at the input and output. Recall how the voltage across the output increases due to decrease in the collector current.
Complete answer:
We know that in Common Emitter configuration, the Emitter is grounded. We apply the input signal between the base and the emitter. The output is taken between the collector and the emitter. To increase the amplitude of the alternating current, we use the common emitter configuration of the transistor as shown in the figure below.
We know that amplifiers amplify the input signal. The voltage gain in the transistor amplifier is the ratio of small change in the output signal across the collector to the small change in the input signal across the base. Therefore,
\[{A_V} = \dfrac{{{v_o}}}{{{v_i}}}\]
\[ \Rightarrow \dfrac{{{v_o}}}{{{v_i}}} = \dfrac{{{I_C}{R_L}}}{{{I_B}{r_i}}}\]
Here, \[{r_i}\] is the input resistance.
We know that the AC current gain is the ratio of collector current to the base current. Therefore,
\[{A_V} = {\beta _{AC}}\dfrac{{{R_L}}}{{{r_i}}}\]
(i) We have the expression for the current gain,
\[{\beta _{AC}} = \dfrac{{{I_C}}}{{{I_B}}}\]
Here, \[{I_C}\] is the collector current and \[{I_B}\] is the base current.
(ii) We have the expression for the voltage gain of the amplifier,
\[{A_V} = {\beta _{AC}}\dfrac{{{R_L}}}{{{r_i}}}\]
Here, \[{R_L}\] is the load resistance and \[{r_i}\] is the input resistance.
Note:The current gain in the C.E transistor as an amplifier has a negative sign which indicates that the output voltage and input voltage are out of phase. Note that the current gain \[{\beta _{AC}}\] is always greater than 1 so that it can increase the voltage across the output. While using a C.E transistor, the input voltage must be applied to the base of the transistor and not to the collector terminal.
Complete answer:
We know that in Common Emitter configuration, the Emitter is grounded. We apply the input signal between the base and the emitter. The output is taken between the collector and the emitter. To increase the amplitude of the alternating current, we use the common emitter configuration of the transistor as shown in the figure below.
![seo images](https://www.vedantu.com/question-sets/943561b5-c41a-4d7d-bc02-0485e08d7d211921705776039542701.png)
We know that amplifiers amplify the input signal. The voltage gain in the transistor amplifier is the ratio of small change in the output signal across the collector to the small change in the input signal across the base. Therefore,
\[{A_V} = \dfrac{{{v_o}}}{{{v_i}}}\]
\[ \Rightarrow \dfrac{{{v_o}}}{{{v_i}}} = \dfrac{{{I_C}{R_L}}}{{{I_B}{r_i}}}\]
Here, \[{r_i}\] is the input resistance.
We know that the AC current gain is the ratio of collector current to the base current. Therefore,
\[{A_V} = {\beta _{AC}}\dfrac{{{R_L}}}{{{r_i}}}\]
(i) We have the expression for the current gain,
\[{\beta _{AC}} = \dfrac{{{I_C}}}{{{I_B}}}\]
Here, \[{I_C}\] is the collector current and \[{I_B}\] is the base current.
(ii) We have the expression for the voltage gain of the amplifier,
\[{A_V} = {\beta _{AC}}\dfrac{{{R_L}}}{{{r_i}}}\]
Here, \[{R_L}\] is the load resistance and \[{r_i}\] is the input resistance.
Note:The current gain in the C.E transistor as an amplifier has a negative sign which indicates that the output voltage and input voltage are out of phase. Note that the current gain \[{\beta _{AC}}\] is always greater than 1 so that it can increase the voltage across the output. While using a C.E transistor, the input voltage must be applied to the base of the transistor and not to the collector terminal.
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