Answer
396.9k+ views
Hint The answer here is dependent on the basic concept of organic chemistry which deals with the reaction mechanism where aldol condensation gives the $\beta -$ hydroxy aldehyde or $\beta -$ hydroxy ketone and decarboxylation is the removal of carboxyl group.
Complete answer:
Let us now see in detail about these two reactions given and write their mechanism of reaction.
(i) Aldol condensation:
Aldol condensation as the name itself says is the condensation of an enol or enolate ion with the carbonyl compound to form a $\beta -$ hydroxy aldehyde or $\beta -$ hydroxy ketone which is followed by dehydration to give a conjugated enone.
The step by step mechanism by citing an example as general reaction can be explained as shown below,
The carboxylic addition to the enol group reacts in a protonated form where the addition product is obtained which on dehydration yields the condensation product.
(ii) Decarboxylation is the chemical reaction which removes a carboxyl group with the release of carbon dioxide gas. Here, there is removal of one carbon atom which comes out as $C{{O}_{2}}$
The general reaction for this process is given as shown below,
Therefore, the product forms is the alkane and carbon dioxide in the above case
Note: Note that the aldol condensation takes place only if there is $\alpha -$ hydrogen atom because the aldol condensation requires the formation of the enolate ion or enol and the absence of$\alpha -$hydrogen do not give these intermediates.
Complete answer:
Let us now see in detail about these two reactions given and write their mechanism of reaction.
(i) Aldol condensation:
Aldol condensation as the name itself says is the condensation of an enol or enolate ion with the carbonyl compound to form a $\beta -$ hydroxy aldehyde or $\beta -$ hydroxy ketone which is followed by dehydration to give a conjugated enone.
The step by step mechanism by citing an example as general reaction can be explained as shown below,
![seo images](https://www.vedantu.com/question-sets/d6cc964e-4695-4089-98f6-6e39103df2a4660449013877689965.png)
The carboxylic addition to the enol group reacts in a protonated form where the addition product is obtained which on dehydration yields the condensation product.
(ii) Decarboxylation is the chemical reaction which removes a carboxyl group with the release of carbon dioxide gas. Here, there is removal of one carbon atom which comes out as $C{{O}_{2}}$
The general reaction for this process is given as shown below,
![seo images](https://www.vedantu.com/question-sets/b0aad3ee-f850-4e83-81bb-7de13d04cbb11397708998730829752.png)
Therefore, the product forms is the alkane and carbon dioxide in the above case
Note: Note that the aldol condensation takes place only if there is $\alpha -$ hydrogen atom because the aldol condensation requires the formation of the enolate ion or enol and the absence of$\alpha -$hydrogen do not give these intermediates.
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