Answer

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Hint: At first construct the matrix by putting ${{a}_{ij}}$, with the actual values of $i,j$ . Then calculate the numerical values by using ${{a}_{ij}}=\dfrac{{{\left( i+j \right)}^{2}}}{2}$.

When some numbers are arranged in rows and columns and are surrounded on both sides by square brackets, we call it a matrix.

Here we have to construct a $2\times 2$ matrix named $A$ .

Now, this $2\times 2$ is known as the order of the matrix. Order of matrices helps us to know how many rows and how many columns there are in a matrix.

Generally we denote the order of a matrix by $m\times n$, where $m$ denotes the number of rows and $n$ denotes the number of columns. Here the order of the matrix is $2\times 2$ . That means this matrix has 2 rows and 2 columns.

Now, the elements of the matrix are generally denoted by ${{a}_{ij}}$. Where $ij$ help us to understand the actual position of the element.

In a matrix $A$, an element in row $i$ and column $j$ is represented by ${{a}_{ij}}$.

${{a}_{11}}$ is the element in 1st row and 1st column.

${{a}_{12}}$ is the element in 1st row and 2nd column.

${{a}_{21}}$ is the element in the 2nd row and 1st column.

${{a}_{22}}$ is the element in the 2nd row and 2nd column.

Therefore, $A=\left[ \begin{matrix}

{{a}_{11}} & {{a}_{12}} \\

{{a}_{21}} & {{a}_{22}} \\

\end{matrix} \right]$

Now let us substitute the values.

${{a}_{11}}=\dfrac{{{\left( 1+1 \right)}^{2}}}{2}=\dfrac{{{2}^{2}}}{2}=2$, here i is 1 and j is 1.

${{a}_{12}}=\dfrac{{{\left( 1+2 \right)}^{2}}}{2}=\dfrac{{{3}^{2}}}{2}=\dfrac{9}{2}$, here i is 1 and j is 2.

${{a}_{21}}=\dfrac{{{\left( 2+1 \right)}^{2}}}{2}=\dfrac{{{3}^{2}}}{2}=\dfrac{9}{2}$, here i is 2 and j is 1.

${{a}_{22}}=\dfrac{{{\left( 2+2 \right)}^{2}}}{2}=\dfrac{{{4}^{2}}}{2}=\dfrac{16}{2}=8$, here i is 2 and j is 2.

Therefore,

$A=\left[ \begin{matrix}

{{a}_{11}} & {{a}_{12}} \\

{{a}_{21}} & {{a}_{22}} \\

\end{matrix} \right]=\left[ \begin{matrix}

2 & \dfrac{9}{2} \\

\dfrac{9}{2} & 8 \\

\end{matrix} \right]$

Hence, $A=\left[ \begin{matrix}

2 & \dfrac{9}{2} \\

\dfrac{9}{2} & 8 \\

\end{matrix} \right]$

Note: We generally make mistakes to understand the position of an element in a matrix. Always check the position of the row first then the column.

__Complete step-by-step answer:__When some numbers are arranged in rows and columns and are surrounded on both sides by square brackets, we call it a matrix.

Here we have to construct a $2\times 2$ matrix named $A$ .

Now, this $2\times 2$ is known as the order of the matrix. Order of matrices helps us to know how many rows and how many columns there are in a matrix.

Generally we denote the order of a matrix by $m\times n$, where $m$ denotes the number of rows and $n$ denotes the number of columns. Here the order of the matrix is $2\times 2$ . That means this matrix has 2 rows and 2 columns.

Now, the elements of the matrix are generally denoted by ${{a}_{ij}}$. Where $ij$ help us to understand the actual position of the element.

In a matrix $A$, an element in row $i$ and column $j$ is represented by ${{a}_{ij}}$.

${{a}_{11}}$ is the element in 1st row and 1st column.

${{a}_{12}}$ is the element in 1st row and 2nd column.

${{a}_{21}}$ is the element in the 2nd row and 1st column.

${{a}_{22}}$ is the element in the 2nd row and 2nd column.

Therefore, $A=\left[ \begin{matrix}

{{a}_{11}} & {{a}_{12}} \\

{{a}_{21}} & {{a}_{22}} \\

\end{matrix} \right]$

Now let us substitute the values.

${{a}_{11}}=\dfrac{{{\left( 1+1 \right)}^{2}}}{2}=\dfrac{{{2}^{2}}}{2}=2$, here i is 1 and j is 1.

${{a}_{12}}=\dfrac{{{\left( 1+2 \right)}^{2}}}{2}=\dfrac{{{3}^{2}}}{2}=\dfrac{9}{2}$, here i is 1 and j is 2.

${{a}_{21}}=\dfrac{{{\left( 2+1 \right)}^{2}}}{2}=\dfrac{{{3}^{2}}}{2}=\dfrac{9}{2}$, here i is 2 and j is 1.

${{a}_{22}}=\dfrac{{{\left( 2+2 \right)}^{2}}}{2}=\dfrac{{{4}^{2}}}{2}=\dfrac{16}{2}=8$, here i is 2 and j is 2.

Therefore,

$A=\left[ \begin{matrix}

{{a}_{11}} & {{a}_{12}} \\

{{a}_{21}} & {{a}_{22}} \\

\end{matrix} \right]=\left[ \begin{matrix}

2 & \dfrac{9}{2} \\

\dfrac{9}{2} & 8 \\

\end{matrix} \right]$

Hence, $A=\left[ \begin{matrix}

2 & \dfrac{9}{2} \\

\dfrac{9}{2} & 8 \\

\end{matrix} \right]$

Note: We generally make mistakes to understand the position of an element in a matrix. Always check the position of the row first then the column.

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