Answer
405.3k+ views
HINT: Here, to answer this question you should remember that the given reaction proceeds via substitution mechanism. The reaction cannot be controlled by general physical means once started. The hydrogen atoms will be replaced by chlorine to give the product.
Complete step by step solution:
Here, the reagents given in the reaction are methane and chlorine. When we expose this mixture to ultraviolet light, a substitution reaction takes up giving us chloromethane as a product.
However, the reaction does not stop here as all the hydrogen in the methane can be replaced by chlorine and we can get any of chloromethane, dichloromethane, trichloromethane or tetrachloromethane.
Even maintaining the proportion of chlorine and methane will not give us the desired product but a mixture of products. And, if we add excess chlorine, we will get tetrachloromethane.
If we want chloromethane as the major product, we can carry on the reaction using excess methane so that the probability of chlorine radical hitting methane is higher. Although we will get a mixture of products, we can expect chloromethane yield to be higher.
We can write the reaction as- $C{{H}_{4}}+C{{l}_{2}}\xrightarrow{h\nu }C{{H}_{3}}Cl+HCl$
So, we can understand from the above discussion that $C{{H}_{4}}\text{ to C}{{\text{l}}_{2}}$ ratio should be higher to expect higher yield of $C{{H}_{3}}Cl$.
Therefore, the correct answer is option [A] High.
NOTE: Here, the overall reaction is $C{{H}_{4}}+C{{l}_{2}}\xrightarrow{h\nu }C{{H}_{3}}Cl+HCl$
However, as the reaction proceeds, due to unavailability of methane, the chlorine radical will hit on chloromethane and give us dichloromethane and the reaction will continue till all the hydrogen atoms are replaced.
$\begin{align}
& C{{H}_{4}}+C{{l}_{2}}\to C{{H}_{3}}Cl+HCl \\
& C{{H}_{3}}Cl+C{{l}_{2}}\to C{{H}_{2}}C{{l}_{2}}+HCl \\
& C{{H}_{2}}C{{l}_{2}}+C{{l}_{2}}\to CHC{{l}_{3}}+HCl \\
& CHC{{l}_{3}}+C{{l}_{2}}\to CC{{l}_{4}}+HCl \\
\end{align}$
Complete step by step solution:
Here, the reagents given in the reaction are methane and chlorine. When we expose this mixture to ultraviolet light, a substitution reaction takes up giving us chloromethane as a product.
However, the reaction does not stop here as all the hydrogen in the methane can be replaced by chlorine and we can get any of chloromethane, dichloromethane, trichloromethane or tetrachloromethane.
Even maintaining the proportion of chlorine and methane will not give us the desired product but a mixture of products. And, if we add excess chlorine, we will get tetrachloromethane.
If we want chloromethane as the major product, we can carry on the reaction using excess methane so that the probability of chlorine radical hitting methane is higher. Although we will get a mixture of products, we can expect chloromethane yield to be higher.
We can write the reaction as- $C{{H}_{4}}+C{{l}_{2}}\xrightarrow{h\nu }C{{H}_{3}}Cl+HCl$
So, we can understand from the above discussion that $C{{H}_{4}}\text{ to C}{{\text{l}}_{2}}$ ratio should be higher to expect higher yield of $C{{H}_{3}}Cl$.
Therefore, the correct answer is option [A] High.
NOTE: Here, the overall reaction is $C{{H}_{4}}+C{{l}_{2}}\xrightarrow{h\nu }C{{H}_{3}}Cl+HCl$
However, as the reaction proceeds, due to unavailability of methane, the chlorine radical will hit on chloromethane and give us dichloromethane and the reaction will continue till all the hydrogen atoms are replaced.
$\begin{align}
& C{{H}_{4}}+C{{l}_{2}}\to C{{H}_{3}}Cl+HCl \\
& C{{H}_{3}}Cl+C{{l}_{2}}\to C{{H}_{2}}C{{l}_{2}}+HCl \\
& C{{H}_{2}}C{{l}_{2}}+C{{l}_{2}}\to CHC{{l}_{3}}+HCl \\
& CHC{{l}_{3}}+C{{l}_{2}}\to CC{{l}_{4}}+HCl \\
\end{align}$
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)