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Cell constant has unit:
A. $S{m^{ - 1}}$
B. $m{S^{ - 1}}$
C. ${m^{ - 1}}$
D. ${m^{ - 2}}$

Last updated date: 17th May 2024
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Hint: We need to realize that the electrical conductivity can be estimated by the cell consistent. It is associated with the cathode. It is typically estimated from the opposition of the phone. At the point when potassium chloride arrangement is utilized for estimating obstruction whose conductivity is known.

Complete answer:
We need to see, electrochemistry manages the investigation of physical and synthetic cycles where power is either delivered or devoured. The death of power through an answer of an electrolyte makes the redox responses bring about the wonder of electrolytes. The course of action is called an electrolytic cell. Faraday's law clarifies the connection between the measure of power passed and the measure of substance kept at the anode.
We need to see, an electrochemical cell is produced using two anodes. The two anodes are kept in a similar compartment of liquid electrolyte. One is known as a cathode and the other one is an anode. The cathode is negative and an anode is positive. Decrease happens in the cathode and oxidation happens in the anode. A salt scaffold is associated with the goal that the particles can be passed. A wire finishes the outside circuit through which the electrons stream. The cell steady is the proportion of the distance between two terminals to the space of cross-part of the cathode. It is signified by ${G^*}$ .
From the above discussion, ${G^*} = \dfrac{1}{A}$ ,
Where, one is the distance between the two electrodes. Then, $A$ = area of cross-section of the electrode. The unit of distance is $m$ . The area of unit = ${m^2}$ .
So, that
${G^*} = \dfrac{m}{{{m^2}}} = \dfrac{1}{m} = {m^{ - 1}}$
The cell constant has unit = ${m^{ - 1}}$ .

Therefore, the correct option is (C).

We need to realize that electrochemical cells are not the same as electrolytic cells. Electrolytic cells convert electrical energy to synthetic energy. An outer battery is associated with supply electrons that get through the cathode and go out through the anode.
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