
At infinite dilution, the percentage ionisation of both weak and strong electrolytes is:
A 1%
B 20%
C 50%
D 100%
Answer
232.8k+ views
Hint: Electrolyte can be a liquid or gel which contains ions and can be dissociated into ions by electrolysis. These electrolytes can be strong or weak on the basis of tendency of dissociation. Some electrolytes dissociate fully is called strong electrolyte and which dissociates partially is called weak electrolyte.
Complete step by step solution:
Infinite dilution is basically a solution that contains a large amount of solvent that when addition of more solvent, there is no change in concentration of ions. This means that no matter how much solvent is added to the solution, the properties of the solute the substrate particles and the system will not change.
Now for weak electrolytes addition of solvent increases the degree of dissociation but that is very low compared to the amount of dilution. But at infinite dilution it is assumed that weak electrolytes dissociates fully.
Strong electrolytes always dissociates fully at any concentration. Therefore, dilution does not affect their dissociation. But due to dilution their electrostatic attraction force gets reduced which helps in conduction. At infinite dilution strong electrolytes dissociate fully.
Therefore, at infinite dilution, the percentage ionisation of both weak and strong electrolytes is 100%
So, the correct option is D.
Note:
According to the ohm’s law of resistance, resistance is directly proportional of the length and inversely proportional to the cross sectional area. which can be written as,\[{{R \alpha }}\dfrac{{\text{l}}}{{\text{A}}}\]. Where length is \[{\text{l}}\] and cross sectional area is \[{\text{A}}\] . It can also be written with a proportional constant \[{{\rho }}\] which is called resistivity . Therefore, the formula of resistance is \[{{R = \rho }}\dfrac{{\text{l}}}{{\text{A}}}\] . Conductance is a reciprocal of resistance of the system, \[{{G = }}\dfrac{{\text{1}}}{{\text{R}}}\]where G is conductance. There for the formula of conductance can be written as,\[{\text{G = }}\dfrac{{\text{1}}}{{\text{R}}}{\text{ = }}\dfrac{{\text{1}}}{{{\rho }}}{{ \times }}\dfrac{{\text{A}}}{{\text{l}}}\]. Where\[\dfrac{{\text{1}}}{{{\rho }}}\] can be written with a new term specific conductance or conductivity. Therefore, the formula of conductance is,
\[
{{G = \kappa \times }}\dfrac{{\text{A}}}{{\text{l}}} \\
{{or,G \times }}\dfrac{{\text{l}}}{{\text{A}}}{{ = \kappa }} \\
\]
Complete step by step solution:
Infinite dilution is basically a solution that contains a large amount of solvent that when addition of more solvent, there is no change in concentration of ions. This means that no matter how much solvent is added to the solution, the properties of the solute the substrate particles and the system will not change.
Now for weak electrolytes addition of solvent increases the degree of dissociation but that is very low compared to the amount of dilution. But at infinite dilution it is assumed that weak electrolytes dissociates fully.
Strong electrolytes always dissociates fully at any concentration. Therefore, dilution does not affect their dissociation. But due to dilution their electrostatic attraction force gets reduced which helps in conduction. At infinite dilution strong electrolytes dissociate fully.
Therefore, at infinite dilution, the percentage ionisation of both weak and strong electrolytes is 100%
So, the correct option is D.
Note:
According to the ohm’s law of resistance, resistance is directly proportional of the length and inversely proportional to the cross sectional area. which can be written as,\[{{R \alpha }}\dfrac{{\text{l}}}{{\text{A}}}\]. Where length is \[{\text{l}}\] and cross sectional area is \[{\text{A}}\] . It can also be written with a proportional constant \[{{\rho }}\] which is called resistivity . Therefore, the formula of resistance is \[{{R = \rho }}\dfrac{{\text{l}}}{{\text{A}}}\] . Conductance is a reciprocal of resistance of the system, \[{{G = }}\dfrac{{\text{1}}}{{\text{R}}}\]where G is conductance. There for the formula of conductance can be written as,\[{\text{G = }}\dfrac{{\text{1}}}{{\text{R}}}{\text{ = }}\dfrac{{\text{1}}}{{{\rho }}}{{ \times }}\dfrac{{\text{A}}}{{\text{l}}}\]. Where\[\dfrac{{\text{1}}}{{{\rho }}}\] can be written with a new term specific conductance or conductivity. Therefore, the formula of conductance is,
\[
{{G = \kappa \times }}\dfrac{{\text{A}}}{{\text{l}}} \\
{{or,G \times }}\dfrac{{\text{l}}}{{\text{A}}}{{ = \kappa }} \\
\]
Recently Updated Pages
Types of Solutions in Chemistry: Explained Simply

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions (2025-26)

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 4 The d and f Block Elements (2025-26)

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules (2025-26)

