
All the words that can be formed using alphabets A, H, L, U, R are written as in a dictionary and no alphabet is repeated. What will be the rank of word RAHUL?
A \[71\]
B \[72\]
C \[73\]
D \[74\]
Answer
233.1k+ views
Hint: Permutation is the arrangement of items in some particular sequence. In this question there are five alphabets and need to form words without repeating the alphabets. In the dictionary words are always in alphabetical order. First find all the words that start with each given alphabet. Then check the word that starts with the alphabet R. Then find the rank of the word RAHUL.
Formula Used: \[n! = 1 \times 2 \times 3 \times ... \times n\]
Here, n is natural number.
Complete step by step solution: There are five alphabets A, H, L, U and R. The alphabetical order of the given alphabets is A, H, L, R and U.
Now, calculate number of words starting with alphabet A.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Calculate number of words starting with alphabet H.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Now, calculate number of words starting with alphabet L.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Hence, calculate total numbers words before words starting with R.
Total numbers words before words starting with R \[24 + 24 + 24 = 72\]
The first words starting with R is RAHLU and the second word is RAHUL. Hence, the word RAHLU is at rank 73 and the word RAHUL is at 74.
So, the word RAHUL has Rank 74.
Option ‘D’ is correct
Note: The common mistake happen here by students are taking permutation of all alphabets which is wrong.
Formula Used: \[n! = 1 \times 2 \times 3 \times ... \times n\]
Here, n is natural number.
Complete step by step solution: There are five alphabets A, H, L, U and R. The alphabetical order of the given alphabets is A, H, L, R and U.
Now, calculate number of words starting with alphabet A.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Calculate number of words starting with alphabet H.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Now, calculate number of words starting with alphabet L.
\[\begin{array}{l}4! = 1 \times 2 \times 3 \times 4\\4! = 24\end{array}\]
Hence, calculate total numbers words before words starting with R.
Total numbers words before words starting with R \[24 + 24 + 24 = 72\]
The first words starting with R is RAHLU and the second word is RAHUL. Hence, the word RAHLU is at rank 73 and the word RAHUL is at 74.
So, the word RAHUL has Rank 74.
Option ‘D’ is correct
Note: The common mistake happen here by students are taking permutation of all alphabets which is wrong.
Recently Updated Pages
JEE Advanced 2026 Revision Notes for Vectors - Free PDF Download

JEE Advanced 2026 Revision Notes for Trigonometry - Free PDF Download

JEE Advanced 2026 Surface Chemistry Revision Notes - Free PDF Download

JEE Advanced Study Plan 2026: Expert Tips and Preparation Guide

JEE Advanced 2026 Revision Notes for Chemistry Solutions - Free PDF Download

Solutions Class 12 Notes JEE Advanced Chemistry [PDF]

Trending doubts
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Difference Between Exothermic and Endothermic Reactions Explained

IIT CSE Cutoff: Category‐Wise Opening and Closing Ranks

IIT Fees Structure 2025

Top IIT Colleges in India 2025

Other Pages
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

NCERT Solutions For Class 11 Maths Chapter 12 Limits and Derivatives (2025-26)

