Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

A uniform but increasing with time magnetic field exists in a cylindrical region. The direction of force on an electron at P is
seo images

(A) Towards right
(B) Towards left
(C) Into the plane of paper
(D) Out of the plane of paper

seo-qna
Last updated date: 24th Jul 2024
Total views: 396.9k
Views today: 10.96k
Answer
VerifiedVerified
396.9k+ views
Hint: The magnetic field which exists inside the cylindrical region is varying with time. So electric fields will be induced in the cylindrical region. The direction of the electric force on the electron will be opposite to the electric field.

Formula used: The formula used to solve this question is given by
 $ \vec F = q\vec E $ , here $ \vec F $ is the force on a charge $ q $ due to an electric field $ \vec E $ .

Complete step-by-step solution
We know that the time varying magnetic field produces electric fields, which exist in loops. The direction of the electric fields, whether clockwise or anticlockwise, will be decided by Lenz's law. Since the magnetic field in the cylindrical region is increasing with time into the plane of the paper, the magnetic flux will also increase into the pane of the paper. So the direction of the induced electric fields will be such that the magnetic flux generated inside the cylindrical region is outside the plane of the paper.
From the right hand thumb rule, we get the direction of the loops of the electric field as anticlockwise. So the induced electric fields can be shown as in the following figure.
seo images

We know that the direction of the electric field at a point inside a region of the electric field lines is along the tangent to the electric field line at that point. So the direction of the electric field is as shown below.
seo images

We know that the force on a charged particle by the electric field is given by
 $ \vec F = q\vec E $
Substituting $ q = - e $ for the electron at P, we get
 $ \vec F = - e\vec E $
The above expression shows that the force on the electron must be opposite to the direction of the electric field at P. From the above figure, the direction of the electric field is towards the left. Thus, the direction of force on the electron is towards the right.
Hence, the correct answer is option A.

Note
Do not use the expression for the magnetic force on a charged particle due to a magnetic field for getting the direction of the force. Although the magnetic field exists in the cylindrical region, since the electron is at rest, no magnetic force will be experienced by it.