Answer
414.9k+ views
Hint:-We know the general formula for pressure which is $P = \dfrac{F}{A}$: P = pressure. F = force. A = area. And we know that mass is equal to density times volume. Write pressure in terms of density and form 2 equations for two tanks keeping the pressure the same, then write Torricelli’s equation and solve for the velocity of efflux.
Formula Used:
Here the formula used is:
$P = \dfrac{F}{A}$
Here:
P = pressure.
F = force.
A = area.
$m = d \times v$
m = mass.
d = density.
v = volume.
$v = \sqrt {2gh} $
v = velocity;
g = gravitational acceleration.
h = height.
Complete step-by-step solution:-
Step 1:
Formula for pressure:
$P = \dfrac{F}{A}$ ;
Here put F = ma.
$P = \dfrac{{ma}}{A}$;
Here $m = d \times v$;
$P = \dfrac{{d \times v \times a}}{A}$;
Write the units of area and volume
$P = \dfrac{{\rho \times {m^3} \times a}}{{{m^2}}}$;
Here d = density =$\rho $.
$P = \rho \times m \times a$;
Here m = meter = height = h;
$P = \rho \times h \times a$
Step 2: Here, the pressure that is put on the opening in the water (See the diagram on LHS) tank is equal to the pressure that is put on the water tank with height h (See the diagram on RHS).
\[h{\rho _w}g = {h_o}{\rho _o}g + {h_w}{\rho _w}g\]; …(a = g)
\[h{\rho _w}g = 4 \times 0.9 \times 9.8 + 1 \times 1 \times 9.8\];
\[h \times 10 = 4 \times 0.9 \times 9.8 + 1 \times 1 \times 9.8\]
\[h = 4.6m\];
Step 3:
Apply Torricelli's equation.
$v = \sqrt {2gh} $ ;
Put the given values. Here $g = 9.8m/{s^2}$
$v = \sqrt {2 \times 9.8 \times 4.6} $
$v = \sqrt {9.8 \times 9.2} {\text{ }}m/s$;
Now convert it into cm/s.
$v = \sqrt {920 \times 980{\text{ }}} {\text{c}}m/s$
Final Answer: Option “1” is correct.
Note:- Here first write the general formula for pressure, then write it in terms of density and equate it with a similar equation for another tank where the weight of oil and water are combined. After getting the height apply the Torricelli’s equation and find out the velocity.
Formula Used:
Here the formula used is:
$P = \dfrac{F}{A}$
Here:
P = pressure.
F = force.
A = area.
$m = d \times v$
m = mass.
d = density.
v = volume.
$v = \sqrt {2gh} $
v = velocity;
g = gravitational acceleration.
h = height.
Complete step-by-step solution:-
Step 1:
Formula for pressure:
$P = \dfrac{F}{A}$ ;
Here put F = ma.
$P = \dfrac{{ma}}{A}$;
Here $m = d \times v$;
$P = \dfrac{{d \times v \times a}}{A}$;
Write the units of area and volume
$P = \dfrac{{\rho \times {m^3} \times a}}{{{m^2}}}$;
Here d = density =$\rho $.
$P = \rho \times m \times a$;
Here m = meter = height = h;
$P = \rho \times h \times a$
Step 2: Here, the pressure that is put on the opening in the water (See the diagram on LHS) tank is equal to the pressure that is put on the water tank with height h (See the diagram on RHS).
![seo images](https://www.vedantu.com/question-sets/b077cb45-08ac-4291-b959-2663b9bd19728885796757671471022.png)
\[h{\rho _w}g = {h_o}{\rho _o}g + {h_w}{\rho _w}g\]; …(a = g)
\[h{\rho _w}g = 4 \times 0.9 \times 9.8 + 1 \times 1 \times 9.8\];
\[h \times 10 = 4 \times 0.9 \times 9.8 + 1 \times 1 \times 9.8\]
\[h = 4.6m\];
Step 3:
Apply Torricelli's equation.
$v = \sqrt {2gh} $ ;
Put the given values. Here $g = 9.8m/{s^2}$
$v = \sqrt {2 \times 9.8 \times 4.6} $
$v = \sqrt {9.8 \times 9.2} {\text{ }}m/s$;
Now convert it into cm/s.
$v = \sqrt {920 \times 980{\text{ }}} {\text{c}}m/s$
Final Answer: Option “1” is correct.
Note:- Here first write the general formula for pressure, then write it in terms of density and equate it with a similar equation for another tank where the weight of oil and water are combined. After getting the height apply the Torricelli’s equation and find out the velocity.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)