 # A student observed $31$ Quisqualis plants each with $36$ nodes, $15$ Hibiscus plants each with $21$nodes and $77$ Calotropis plants each with $11$ nodes. All these plants contain leaves at every node. What is the total number of leaves of these three plants put together?A. $2593$B. $1585$C. $237$D. $4241$ Verified
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Hint: Flowers are arranged in the plant in a particular manner, this is called an inflorescence. The same way leaves are also arranged in a plant stem or branch. This arrangement is called phyllotaxy. The position of the leaves is never random; each leaf has a definite place in the stem or branch. This arrangement varies from one plant species to another.

According to the question, $31$ Quisqualis have $36$ nodes. Quisqualis shows the opposite superimposed arrangement. Therefore, there are two leaves at each node.
The total number of leaves for Quiqualis ($31 \times 36 \times 2$) is $2232$. Hibiscus shows alternate phyllotaxy, therefore, the total number of leaves for Hibiscus plants ($15 \times 21$) is $315$. Calotropis shows decussate phyllotaxy, the total number of leaves for Calotropis plants ($77 \times 11 \times 2$) is $1694$. The leaves from all three plants ($2232 + 315 + 1694$), gives a sum total of $4241$.