
A cube of metal is subjected to a hydrostatic pressure of 4GPa. The percentage change in the length of the side of the cube is close to: (Given bulk modulus of metal,\[B = 8 \times {10^{10}}Pa\]
A. 0.6
B. 20
C. 1.67
D. 5
Answer
232.8k+ views
Hint:When the fluid is in an equilibrium position, due to force of gravity a pressure is exerted on the fluid, which is known as hydrostatic pressure.The formula for bulk modulus of elasticity will be applied here. This formula is used when applying pressure. There is some change in volume. It is denoted by symbol B and represented by the units Newton per meter square.
Formula Used:
Mathematically, the Bulk modulus formula is given by,
\[B = \dfrac{{\Delta P}}{{\dfrac{{\Delta V}}{V}}}\]……(i)
Where ‘B’ is the bulk modulus of elasticity, \[\Delta P\] is the change in pressure per unit area, \[\Delta V\] is the change in volume and V is the original or initial volume.
Complete step by step solution:
Given that the pressure is \[\Delta P = 4\,GPa = 4 \times {10^9}Pa\].
Let the length of the side of the cube is ‘a’.
The volume of cube is given by the formula= \[{a^3}\]
Change in volume is given by,
\[\dfrac{{\Delta V}}{V} = 3 \times \dfrac{{\Delta a}}{a}\]
\[\Rightarrow \dfrac{{4 \times {{10}^9}}}{{8 \times {{10}^{10}}}} = 3 \times \dfrac{{\Delta a}}{a}\]
\[\Rightarrow \dfrac{{\Delta a}}{a} = \dfrac{1}{{60}}\]
Calculating the percentage change, we get
\[\dfrac{{\Delta a}}{a} \times 100 = \dfrac{1}{{60}} \times 100\]
\[\therefore \dfrac{{\Delta a}}{a} = 1.67\]
Therefore, the percentage change in the length of the side of the cube is equal to 1.67.
Hence, option C is the correct answer.
Note: It is important to note that the hydrostatic pressure varies with the depth of the liquid. As the depth increases, the pressure also increases. This is because as the depth increases, the bottom layer of the fluid experiences pressures from the top layer, which increases the pressure of the overall container. Therefore, at the bottom of the container, the pressure is maximum and it increases as the depth increases. Also, another factor is that the liquid exerts pressure in all directions.
Formula Used:
Mathematically, the Bulk modulus formula is given by,
\[B = \dfrac{{\Delta P}}{{\dfrac{{\Delta V}}{V}}}\]……(i)
Where ‘B’ is the bulk modulus of elasticity, \[\Delta P\] is the change in pressure per unit area, \[\Delta V\] is the change in volume and V is the original or initial volume.
Complete step by step solution:
Given that the pressure is \[\Delta P = 4\,GPa = 4 \times {10^9}Pa\].
Let the length of the side of the cube is ‘a’.
The volume of cube is given by the formula= \[{a^3}\]
Change in volume is given by,
\[\dfrac{{\Delta V}}{V} = 3 \times \dfrac{{\Delta a}}{a}\]
\[\Rightarrow \dfrac{{4 \times {{10}^9}}}{{8 \times {{10}^{10}}}} = 3 \times \dfrac{{\Delta a}}{a}\]
\[\Rightarrow \dfrac{{\Delta a}}{a} = \dfrac{1}{{60}}\]
Calculating the percentage change, we get
\[\dfrac{{\Delta a}}{a} \times 100 = \dfrac{1}{{60}} \times 100\]
\[\therefore \dfrac{{\Delta a}}{a} = 1.67\]
Therefore, the percentage change in the length of the side of the cube is equal to 1.67.
Hence, option C is the correct answer.
Note: It is important to note that the hydrostatic pressure varies with the depth of the liquid. As the depth increases, the pressure also increases. This is because as the depth increases, the bottom layer of the fluid experiences pressures from the top layer, which increases the pressure of the overall container. Therefore, at the bottom of the container, the pressure is maximum and it increases as the depth increases. Also, another factor is that the liquid exerts pressure in all directions.
Recently Updated Pages
Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Circuit Switching vs Packet Switching: Key Differences Explained

Dimensions of Pressure in Physics: Formula, Derivation & SI Unit

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

