NCERT Solutions for Class 9 Maths Chapter 14 Statistics (Ex 14.2) Exercise 14.2
Free PDF download of NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.2 (Ex 14.2) and all chapter exercises at one place prepared by expert teacher as per NCERT (CBSE) books guidelines. Class 9 Maths Chapter 14 Statistics Exercise 14.2 Questions with Solutions to help you to revise complete Syllabus and Score More marks. Register and get all exercise NCERT Solutions in your emails. Students can also avail of NCERT Solutions Class 9 Science from our website.
NCERT Solutions for Class 9 Maths Chapter 14 - Exercise

Access NCERT solutions for Class 9 Maths Chapter 14 โ Statistics
Exercise 14.2
1. The blood groups of $30$ students of Class $VIII$ are recorded as follows: $A,B,O,O,AB,O,A,O,B,A,O,B,A,O,O,A,AB,O,A,A,O,O,AB,B,A,O,B,A,B,O$. Represent this data in the form of a frequency distribution table. Which is the most common, and which is the rarest, blood group among these students?
Ans: From the question we can observe that the students having blood group $A$ are $9$, students having blood group $B$ are $6$, students having blood group $AB$ are $3$ and the students having blood group $O$ are $12$.
Its table will be of the form:
Type of Blood Group | No. of Students |
A | 9 |
B | 6 |
AB | 3 |
0 | 12 |
Total | 30 |
From the table we can observe that the blood group $O$ is the most common and the blood group $AB$ is the rarest.
2. The distance (in km) of $40$ engineers from their residence to their place of work were found as follows:
\[\begin{align} & \mathbf{5}\text{ }\mathbf{3}\text{ }\mathbf{10}\text{ }\mathbf{20}\text{ }\mathbf{25}\text{ }\mathbf{11}\text{ }\mathbf{13}\text{ }\mathbf{7}\text{ }\mathbf{12}\text{ }\mathbf{31}\text{ }\mathbf{19}\text{ }\mathbf{10}\text{ }\mathbf{12}\text{ }\mathbf{17}\text{ }\mathbf{18}\text{ }\mathbf{11}\text{ }\mathbf{32}\text{ }\mathbf{17}\text{ }\mathbf{16}\text{ }\mathbf{2}\text{ }\mathbf{7}\text{ }\mathbf{9}\text{ }\mathbf{7}\text{ }\mathbf{8}\text{ }\mathbf{3}\text{ }\mathbf{5}\text{ }\mathbf{12}\text{ }\mathbf{15}\text{ }\mathbf{18}\text{ } \\ & \mathbf{3}\text{ }\mathbf{12}\text{ }\mathbf{14}\text{ }\mathbf{2}\text{ }\mathbf{9}\text{ }\mathbf{6}\text{ }\mathbf{15}\text{ }\mathbf{15}\text{ }\mathbf{7}\text{ }\mathbf{6}\text{ }\mathbf{12} \\ \end{align}\]
Construct a grouped frequency distribution table with class size $5$ for the data given above taking the first interval as $0-5$ ($5$ not included). What main feature do you observe from this tabular representation?
Ans: The grouped frequency distribution table with class size $5$ for the given data will be:
Distance (in km) | Tally Marks | Frequency |
0-5 | (Image will be uploaded soon) | 5 |
5-10 | (Image will be uploaded soon) | 11 |
10-15 | (Image will be uploaded soon) | 11 |
15-20 | (Image will be uploaded soon) | 9 |
20-25 | | | 1 |
25-30 | | | 1 |
30-35 | || | 2 |
Total |
| 40 |
From the table representation above, we can observe that most of the engineers from their residence to the place they work lies below and between the range of $15-20$.
3. The relative humidity (in %) of a certain city for a month of $30$ days was as follows:
\[\begin{align} & \mathbf{98}.\mathbf{1}\text{ }\mathbf{98}.\mathbf{6}\text{ }\mathbf{99}.\mathbf{2}\text{ }\mathbf{90}.\mathbf{3}\text{ }\mathbf{86}.\mathbf{5}\text{ }\mathbf{95}.\mathbf{3}\text{ }\mathbf{92}.\mathbf{9}\text{ }\mathbf{96}.\mathbf{3}\text{ }\mathbf{94}.\mathbf{2}\text{ }\mathbf{95}.\mathbf{1}\ \ \mathbf{89}.\mathbf{2}\text{ }\mathbf{92}.\mathbf{3}\text{ }\mathbf{97}.\mathbf{1}\text{ }\mathbf{93}.\mathbf{5}\text{ }\mathbf{92}.\mathbf{7}\text{ }\mathbf{95}.\mathbf{1}\text{ } \\ & \mathbf{97}.\mathbf{2}\text{ }\mathbf{93}.\mathbf{3}\text{ }\mathbf{95}.\mathbf{2}\text{ }\mathbf{97}.\mathbf{3}\text{ }\mathbf{96}.\mathbf{2}\text{ }\mathbf{92}.\mathbf{1}\text{ }\mathbf{84}.\mathbf{9}\text{ }\mathbf{90}.\mathbf{2}\text{ }\mathbf{95}.\mathbf{7}\text{ }\mathbf{98}.\mathbf{3}\text{ }\mathbf{97}.\mathbf{3}\text{ }\mathbf{96}.\mathbf{1}\text{ }\mathbf{92}.\mathbf{1}\text{ }\mathbf{89} \\ \end{align}\]
(i). Construct a grouped frequency distribution table with classes $84-86,86-88$ etc.
Ans: The grouped frequency distribution table with classes $84-86,86-88$ and so on will be of the form:
Relative Humidity (in %) | Number of Days |
84-86 | 1 |
86-88 | 1 |
88-90 | 2 |
90-92 | 2 |
92-94 | 7 |
94-96 | 6 |
96-98 | 7 |
98-100 | 4 |
Total | 30 |
(ii). Which month or season do you think this data is about?
Ans: As, the humidity is very high in percentage, hence the data could be of the monsoon season in the month of June โ July.
(iii). What is the range of this data?
Ans: The range of the data can be calculated by $Range=Maximum\ value-Minimum\ value$
$\Rightarrow 99.2-84.9=14.3$
4. The heights of 50 students, measured to the nearest centimetres, have been found to be as follows:
\[\begin{align} & \mathbf{161}\text{ }\mathbf{150}\text{ }\mathbf{154}\text{ }\mathbf{165}\text{ }\mathbf{168}\text{ }\mathbf{161}\text{ }\mathbf{154}\text{ }\mathbf{162}\text{ }\mathbf{150}\text{ }\mathbf{151}\text{ }\mathbf{162}\text{ }\mathbf{164}\text{ }\mathbf{171}\text{ }\mathbf{165}\text{ }\mathbf{158}\text{ }\mathbf{154}\text{ } \\ & \mathbf{156}\text{ }\mathbf{172}\text{ }\mathbf{160}\text{ }\mathbf{170}\text{ }\mathbf{153}\text{ }\mathbf{159}\text{ }\mathbf{161}\text{ }\mathbf{170}\text{ }\mathbf{162}\text{ }\mathbf{165}\text{ }\mathbf{166}\text{ }\mathbf{168}\text{ }\mathbf{165}\text{ }\mathbf{164}\text{ }\mathbf{154}\text{ }\mathbf{152}\text{ } \\ & \mathbf{153}\text{ }\mathbf{156}\text{ }\mathbf{158}\text{ }\mathbf{162}\text{ }\mathbf{160}\text{ }\mathbf{161}\text{ }\mathbf{173}\text{ }\mathbf{166}\text{ }\mathbf{161}\text{ }\mathbf{159}\text{ }\mathbf{162}\text{ }\mathbf{167}\text{ }\mathbf{168}\text{ }\mathbf{159}\text{ }\mathbf{158}\text{ }\mathbf{153}\text{ }\mathbf{154}\text{ }\mathbf{159} \\ \end{align}\]
(i). Represent the data given above by a grouped frequency distribution table, taking the class intervals as $160-165,165-170$, etc.
Ans: The grouped frequency distribution table, taking the class intervals as $160-165,165-170$, etc will be of the form:
Heights (in cm) | Number of Students |
150-155 | 12 |
155-160 | 9 |
160-165 | 14 |
165-170 | 10 |
170-175 | 5 |
Total | 50 |
(ii). What can you conclude about their heights from the table?
Ans: We can conclude from the table that almost $70%$ of the students have height less than $165cm$.
5. A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for $30$ days is as follows:
\[\begin{align} & \mathbf{0}.\mathbf{03}\text{ }\mathbf{0}.\mathbf{08}\text{ }\mathbf{0}.\mathbf{08}\text{ }\mathbf{0}.\mathbf{09}\text{ }\mathbf{0}.\mathbf{04}\text{ }\mathbf{0}.\mathbf{17}\text{ }\mathbf{0}.\mathbf{16}\text{ }\mathbf{0}.\mathbf{05}\text{ }\mathbf{0}.\mathbf{02}\text{ }\mathbf{0}.\mathbf{06}\text{ }\mathbf{0}.\mathbf{18}\text{ }\mathbf{0}.\mathbf{20}\text{ }\mathbf{0}.\mathbf{11}\text{ }\mathbf{0}.\mathbf{08}\text{ }\mathbf{0}.\mathbf{12}\text{ } \\ & \mathbf{0}.\mathbf{13}\text{ }\mathbf{0}.\mathbf{22}\text{ }\mathbf{0}.\mathbf{07}\text{ }\mathbf{0}.\mathbf{08}\text{ }\mathbf{0}.\mathbf{01}\text{ }\mathbf{0}.\mathbf{10}\text{ }\mathbf{0}.\mathbf{06}\text{ }\mathbf{0}.\mathbf{09}\text{ }\mathbf{0}.\mathbf{18}\text{ }\mathbf{0}.\mathbf{11}\text{ }\mathbf{0}.\mathbf{07}\text{ }\mathbf{0}.\mathbf{05}\text{ }\mathbf{0}.\mathbf{07}\text{ }\mathbf{0}.\mathbf{01}\text{ }\mathbf{0}.\mathbf{04} \\ \end{align}\]
(i). Make a grouped frequency distribution table for this data with class intervals as \[\mathbf{0}.\mathbf{00}\mathbf{0}.\mathbf{04},\text{ }\mathbf{0}.\mathbf{04}\mathbf{0}.\mathbf{08}\], and so on.
Ans: The grouped frequency distribution table for this data with class intervals as $0.00-0.04,\ 0.04-0.08$, and so on will be of the form:
Concentration of S02 (in ppm) | Number of Days |
0.00-0.04 | 4 |
0.04-0.08 | 9 |
0.08-0.12 | 9 |
0.12-0.16 | 2 |
0.16-0.20 | 4 |
0.20-0.24 | 2 |
Total | 30 |
(ii).For how many days, was the concentration of sulphur dioxide more than $0.11$ parts per million?
Ans: From the table we can observe that the concentrations of sulphur dioxide that are more than $0.11$ are $0.12-0.16,\ 0.16-0.20$ and $0.20-0.24$. Hence, the number of days the concentration is more than $0.11$ will be โ
$2+4+2=8\ days$.
6. Three coins were tossed $30$ times simultaneously. Each time the number of heads occurring was noted down as follows:
\[\mathbf{0}\text{ }\mathbf{1}\text{ }\mathbf{2}\text{ }\mathbf{2}\text{ }\mathbf{1}\text{ }\mathbf{2}\text{ }\mathbf{3}\text{ }\mathbf{1}\text{ }\mathbf{3}\text{ }\mathbf{0}\text{ }\mathbf{1}\text{ }\mathbf{3}\text{ }\mathbf{1}\text{ }\mathbf{1}\text{ }\mathbf{2}\text{ }\mathbf{2}\text{ }\mathbf{0}\text{ }\mathbf{1}\text{ }\mathbf{2}\text{ }\mathbf{1}\text{ }\mathbf{3}\text{ }\mathbf{0}\text{ }\mathbf{0}\text{ }\mathbf{1}\text{ }\mathbf{1}\text{ }\mathbf{2}\text{ }\mathbf{3}\text{ }\mathbf{2}\text{ }\mathbf{2}\text{ }\mathbf{0}\]
Prepare a frequency distribution table for the data given above.
Ans: From the given data, the frequency distribution table will be in the form:
Number of Heads | Number of Times Heads Occurred |
0 | 6 |
1 | 10 |
2 | 9 |
3 | 5 |
Total | 30 |
7. The value of $\pi $ up to $50$ decimal places is given below: \[\mathbf{3}.\mathbf{14159265358979323846264338327950288419716939937510}\]
(i). Make a frequency distribution of the digits from $0\ to\ 9$ after the decimal point.
Ans: The frequency distribution table of the digits from $0\ to\ 9$ after the decimal point will be of the form:
Digit | Frequency |
0 | 2 |
1 | 5 |
2 | 5 |
3 | 8 |
4 | 4 |
5 | 5 |
6 | 4 |
7 | 4 |
8 | 5 |
9 | 8 |
Total | 50 |
(ii). What are the most and the least frequently occurring digits?
Ans: The most frequently occurring digits are $3$ and $9$ with frequency $8$ and the least frequently occurring digit is $0$.
8. Thirty children were asked about the number of hours they watched TV programmes in the previous week. The results were found as follows:
\[1\ \ \mathbf{6}\text{ }\mathbf{2}\text{ }\mathbf{3}\text{ }\mathbf{5}\text{ }\mathbf{12}\text{ }\mathbf{5}\text{ }\mathbf{8}\text{ }\mathbf{4}\text{ }\mathbf{8}\text{ }\mathbf{10}\text{ }\mathbf{3}\text{ }\mathbf{4}\text{ }\mathbf{12}\text{ }\mathbf{2}\text{ }\mathbf{8}\text{ }\mathbf{15}\text{ }\mathbf{1}\text{ }\mathbf{17}\text{ }\mathbf{6}\text{ }\mathbf{3}\text{ }\mathbf{2}\text{ }\mathbf{8}\text{ }\mathbf{5}\text{ }\mathbf{9}\text{ }\mathbf{6}\text{ }\mathbf{8}\text{ }\mathbf{7}\text{ }\mathbf{14}\text{ }\mathbf{12}\]
(i). Make a grouped frequency distribution table for this data, taking class width $5$ and one of the class intervals as $5-10$.
Ans: The grouped frequency distribution table for the data given taking class width $5$ and one of the class intervals as $5-10$ will be of the form:
Hours | Number of Children |
0-5 | 10 |
5-10 | 13 |
10-15 | 5 |
15-20 | 2 |
Total | 30 |
(ii). How many children watched television for $15$ or more hours a week?
Ans: From the table above, we can observe that the number of children who watched television for $15$ or more hours a week is $2$.
9: A company manufactures car batteries of a particular type. The lives (in years) of $40$ such batteries were recorded as follows:
\[\begin{align} & \mathbf{2}.\mathbf{6}\text{ }\mathbf{3}.\mathbf{0}\text{ }\mathbf{3}.\mathbf{7}\text{ }\mathbf{3}.\mathbf{2}\text{ }\mathbf{2}.\mathbf{2}\text{ }\mathbf{4}.\mathbf{1}\text{ }\mathbf{3}.\mathbf{5}\text{ }\mathbf{4}.\mathbf{5}\text{ }\mathbf{3}.\mathbf{5}\text{ }\mathbf{2}.\mathbf{3}\text{ }\mathbf{3}.\mathbf{2}\text{ }\mathbf{3}.\mathbf{4}\text{ }\mathbf{3}.\mathbf{8}\text{ }\mathbf{3}.\mathbf{2}\text{ }\mathbf{4}.\mathbf{6}\text{ }\mathbf{3}.\mathbf{7}\text{ }\mathbf{2}.\mathbf{5}\text{ }\mathbf{4}.\mathbf{4}\text{ }\mathbf{3}.\mathbf{4}\text{ }\mathbf{3}.\mathbf{3}\text{ } \\ & \mathbf{2}.\mathbf{9}\text{ }\mathbf{3}.\mathbf{0}\text{ }\mathbf{4}.\mathbf{3}\text{ }\mathbf{2}.\mathbf{8}\text{ }\mathbf{3}.\mathbf{5}\text{ }\mathbf{3}.\mathbf{2}\text{ }\mathbf{3}.\mathbf{9}\text{ }\mathbf{3}.\mathbf{2}\text{ }\mathbf{3}.\mathbf{2}\text{ }\mathbf{3}.\mathbf{1}\text{ }\mathbf{3}.\mathbf{7}\text{ }\mathbf{3}.\mathbf{4}\text{ }\mathbf{4}.\mathbf{6}\text{ }\mathbf{3}.\mathbf{8}\text{ }\mathbf{3}.\mathbf{2}\text{ }\mathbf{2}.\mathbf{6}\text{ }\mathbf{3}.\mathbf{5}\text{ }\mathbf{4}.\mathbf{2}\text{ }\mathbf{2}.\mathbf{9}\text{ }\mathbf{3}.\mathbf{6} \\ \end{align}\]Construct a grouped frequency distribution table for this data, using class intervals of size \[\mathbf{0}.\mathbf{5}\] starting from the intervals \[\mathbf{2}-\mathbf{2}.\mathbf{5}\].
Ans: The grouped frequency distribution table for the given data using the class intervals of size $0.5$ starting from the intervals $2-2.5$.
Lives of Batteries (in hrs) | Number of Batteries |
2-2.5 | 2 |
2.5-3 | 6 |
3-3.5 | 14 |
3.5-4 | 11 |
4-4.5 | 4 |
4.5-5 | 3 |
Total | 40 |
NCERT Solutions for Class 9 Maths Chapter 14 Statistics Exercise 14.2
Opting for the NCERT solutions for Ex 14.2 Class 9 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 14.2 Class 9 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.
Vedantu in-house subject matter experts have solved the problems/ questions from the exercise with the utmost care and by following all the guidelines by CBSE. Class 9 students who are thorough with all the concepts from the Subject Statistics textbook and quite well-versed with all the problems from the exercises given in it, then any student can easily score the highest possible marks in the final exam. With the help of this Class 9 Maths Chapter 14 Exercise 14.2 solutions, students can easily understand the pattern of questions that can be asked in the exam from this chapter and also learn the marks weightage of the chapter. So that they can prepare themselves accordingly for the final exam.
Besides these NCERT solutions for Class 9 Maths Chapter 14 Exercise 14.2, there are plenty of exercises in this chapter which contain innumerable questions as well. All these questions are solved/answered by our in-house subject experts as mentioned earlier. Hence all of these are bound to be of superior quality and anyone can refer to these during the time of exam preparation. In order to score the best possible marks in the class, it is really important to understand all the concepts of the textbooks and solve the problems from the exercises given next to it.
Do not delay any more. Download the NCERT solutions for Class 9 Maths Chapter 14 Exercise 14.2 from Vedantu website now for better exam preparation. If you have the Vedantu app in your phone, you can download the same through the app as well. The best part of these solutions is these can be accessed both online and offline as well.




















