Class 6 Maths Chapter 3 Questions and Answers - Free PDF Download
FAQs on NCERT Solutions For Class 6 Maths Chapter 3 Number Play Exercise 3.12 - 2025-26
1. Where can I find reliable and step-by-step NCERT Solutions for Class 6 Maths Chapter 3, Number Play, for the 2025-26 session?
You can find comprehensive and accurate NCERT Solutions for Class 6 Maths Chapter 3 Number Play on Vedantu. These solutions are prepared by subject matter experts and follow the latest CBSE 2025-26 guidelines, providing clear, step-by-step explanations for every question in the textbook exercises to help you build a strong conceptual foundation.
2. What is the correct method to find the HCF of two numbers using prime factorisation as shown in Chapter 3?
To find the Highest Common Factor (HCF) using the prime factorisation method, you should follow these steps:
- Step 1: Find the prime factors of each number separately.
- Step 2: Identify the common prime factors from the lists of factors for all the numbers.
- Step 3: Multiply these common prime factors together. The product is the HCF of the given numbers. For example, for 12 and 18, the prime factors are 2×2×3 and 2×3×3. The common factors are 2 and 3, so the HCF is 2×3 = 6.
3. How do you solve for the LCM of numbers using the common division method in Class 6 Maths Chapter 3?
The common division method is an efficient way to find the Lowest Common Multiple (LCM). Here is the step-by-step process:
- Step 1: Arrange the given numbers in a row, separated by commas.
- Step 2: Divide the numbers by the smallest prime number that can divide at least one of them.
- Step 3: Write the quotients and any undivided numbers in the row below.
- Step 4: Repeat this process until all the numbers in the last row become 1.
- Step 5: The product of all the prime divisors you used is the LCM of the numbers.
4. How do the NCERT Solutions on Vedantu make solving problems from Chapter 3, Number Play, easier?
Vedantu's NCERT Solutions for Chapter 3 simplify learning by breaking down complex problems into easy-to-understand steps. They explain the logic behind divisibility tests, finding HCF and LCM, and handling word problems. Each solution is crafted to align with the CBSE marking scheme, ensuring you learn the correct method to score full marks in exams. For a complete understanding, you can refer to the Class 6 Maths Chapter 3 Number Play Notes which summarises all key concepts.
5. What is the fundamental difference between HCF and LCM, and how do I know which one to use for word problems in this chapter?
The key difference is that HCF (Highest Common Factor) is the largest number that can divide a set of numbers without leaving a remainder, while LCM (Lowest Common Multiple) is the smallest number that is a multiple of all numbers in the set. Use HCF when a problem asks for finding the largest item to 'split' or 'distribute' things into equal groups. Use LCM when a problem involves finding a common time or point when events will happen 'together again'.
6. Why is the number 1 considered neither a prime number nor a composite number in mathematics?
The number 1 is unique because it has only one factor: itself. The definition of a prime number requires it to have exactly two distinct factors (1 and itself). The definition of a composite number requires it to have more than two factors. Since 1 does not fit either of these definitions, it is classified as neither prime nor composite. You can explore more about prime and composite numbers to understand their properties better.
7. How do I solve the problems in Exercise 3.7 of Chapter 3, which often involve real-life applications of HCF and LCM?
The word problems in Exercise 3.7 require you to first identify whether to calculate HCF or LCM. For questions asking about maximum capacity, longest tape, or arranging items in groups, you typically need to find the HCF. For questions about finding when things will happen simultaneously again (like bells ringing together), you need to find the LCM. For detailed, stepwise answers, you can refer to Vedantu's NCERT Solutions for Class 6 Maths Ch 3 Number Play Ex 3.7.
8. What is the correct way to apply the divisibility test for 11 as per the NCERT textbook?
To check if a number is divisible by 11, follow this method:
- Step 1: Find the sum of the digits at the odd places (from the right).
- Step 2: Find the sum of the digits at the even places (from the right).
- Step 3: Calculate the difference between these two sums.
- Step 4: If the difference is either 0 or a multiple of 11, the number is divisible by 11. Otherwise, it is not.























